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2 years ago

PLEASE HELP MEEEEEE!!!!!!!!!!!!!!!!!!

Physics

2 answers:

Simora [160]2 years ago

5 0

You would need to freeze it in a freezer. Hope this helps if it does could I have brainlist thanks

MAXImum [283]2 years ago

3 0

When liquid water loses thermal energy, it undergoes freezing : changing state from a liquid to a solid. We see many examples of this in everyday life. Puddles, ponds, lakes, and even parts of oceans freeze when the water becomes cold enough. At low temperatures, Earth's surface water freezes and forms solid ice.

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The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the

seraphim [82]

Answer:

$x=\dfrac{D}{1+\sqrt{\dfrac{m}{M}}}$

Explanation:

Mass of moon = m

Mass of planet =M

We know that gravitational force given as

$F=G\dfrac{m_1m_2}{d^2}$

$F'=G\dfrac{m'M}{x^2}$

$F=G\dfrac{m'm}{(D-x)^2}$

Given that force is zero so

F=F'

$G\dfrac{m'm}{(D-x)^2}=G\dfrac{m'M}{x^2}$

$\dfrac{m}{(D-x)^2}=\dfrac{M}{x^2}$

$\dfrac{x}{D-x}=\sqrt{\dfrac{M}{m}}$

$\dfrac{D-x}{x}=\sqrt{\dfrac{m}{M}}$

$x=\dfrac{D}{1+\sqrt{\dfrac{m}{M}}}$

6 0

3 years ago

Is the text in red correct (0n0')

Ede4ka [16]

Yes the text in the red is correct.

8 0

3 years ago

I have another one of these similar to it, if you need another 20 points then look in my profile.

zimovet [89]

Answer:

NEW

Explanation:

As the moon moves to position Z it becomes a New moon due to the light of the sun shining on it

8 0

2 years ago

Read 2 more answers

Spymaster Paul, flying a constant 215km/h horizontally in a low-flying helicopter, want to drop secret documents into his contac

aleksandrvk [35]

Answer:

$\theta = 49.56 degree$

Explanation:

Relative horizontal velocity of plane with respect to the car is given as

$v_r = v_p - v_c$

so we have

$v_p = 215 km/h$

$v_c = 155 km/h$

now we have

$v_r = 215 - 155$

$v_r = 60 km/h$

$v_r = 16.67 m/s$

Now time taken by the object to drop the vertical height is given as

$y = \frac{1}{2}gt^2$

$78 = \frac{1}{2}(9.81)t^2$

$t = 3.98 s$

so the distance of the car must be

$d = v_r\times t$

$d = 16.67 \times 3.98$

$d = 66.47 m$

Angle of the car with horizontal is given as

$tan\theta = \frac{y}{x}$

$tan\theta = \frac{78}{66.47}$

$\theta = tan^{-1}(1.17)$

$\theta = 49.56 degree$

5 0

3 years ago

Two conducting spheres are mounted on insulating rods. They both carry some initial electric charge, and are far from any other

natka813 [3]

The question is incomplete. The complete question is :

Two conducting spheres are mounted on insulating rods. They both carry some initial electric charge, and are far from any other charge. Their charges are measured. Then, the spheres are allowed to briefly touch, and the charge in one of them (sphere A) is measured again. These are the measured values:

a). Before contact:

Sphere A = 4.8 nC

Sphere B = 0 nC

What is the charge on sphere B after contact, in nC?

b). Before contact:

Sphere A = 2.9 nC

Sphere B = -4.4 nC

What is the charge on sphere B after contact, in nC?

Solution :

It is given that there are two spheres that are conducting and are mounted on an insulating rods which carry a initial charge and they are briefly touched and then one of the charge is measured.

Here the charge becomes divided when both the spheres are connected and then removed.

a). charge after they are charged

$Q = \frac{q_1+q_2}{2}$