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3 years ago

PLEASE HELP MEEEEEE!!!!!!!!!!!!!!!!!!

Physics

2 answers:

Simora [160]3 years ago

5 0

You would need to freeze it in a freezer. Hope this helps if it does could I have brainlist thanks

MAXImum [283]3 years ago

3 0

When liquid water loses thermal energy, it undergoes freezing : changing state from a liquid to a solid. We see many examples of this in everyday life. Puddles, ponds, lakes, and even parts of oceans freeze when the water becomes cold enough. At low temperatures, Earth's surface water freezes and forms solid ice.

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Donna is leaming about the water cycle in school. She knows that runoff is water that flows over land surfaces,

77julia77 [94]

Answer:

ummm imma need the picture bud

Explanation:

7 0

3 years ago

A single-turn circular loop of wire that has a radius of 3.5 cm lies in the plane perpendicular to a spatially uniform magnetic

Lena [83]

Explanation:

Given that,

Radius of the circular loop, r = 3.5 cm = 0.035 m

(a) During a 0.12-s time interval, the magnitude of the field increases uniformly from 0.2 T to 0.5 T. Due to the change in the magnetic field, an emf will induced in it. The magnitude of induced emf is given by :

$\epsilon=-\dfrac{d(BA)}{dt}\\\\\epsilon=-\pi r^2\dfrac{B_f-B_i}{dt}\\\\\epsilon=-\pi (0.035)^2\dfrac{0.5-0.2}{0.12}\\\\\epsilon=-9.62\times 10^{-3}\ volts$

So, the magnitude of the emf induced in the loop during the time interval is $9.62\times 10^{-3}\ V$ .

(b) The negative sign shows that the direction of induced emf in the loop is in anitclockwise direction.

5 0

3 years ago

A 0.150 kg ball is fired from toy gun with a spring with spring constant k- 150 N/m, initially compressed by a distance x 0.050

Degger [83]

Answer:

v = 4.264 m/s

Explanation:

It is given that,

Mass of the ball, m = 0.15 kg

Spring constant of the spring, k = 150 N/m

The spring is compressed by a distance, x = 0.05 m

The pellet's initial velocity is at an angle θ (θ < 90) above the horizontal.

Let v is the final speed of the projectile when it is at a distance h = 0.800 m below its initial height. It can be calculated using the conservation of energy as :

$E_i=E_f$

$\dfrac{1}{2}kx^2+mgh=\dfrac{1}{2}mv^2$

$\dfrac{1}{2}\times 150\times (0.05)^2+0.15\times 9.8\times 0.8=\dfrac{1}{2}\times 0.15\times v^2$

v = 4.264 m/s

So, the final speed of the projectile is 4.264 m/s. Hence, this is the required solution.

3 0

3 years ago

A ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor. part a how long will it take the ball to hi

elena55 [62]

Working formula:

y = v*t + 0.5*a*t^2

where:
y = vertical distance = -1 m
v = initial velocity = 1.25m/s
a = acceleration = 9.81 m/s^2
t = time

Required: t

Solution:

y = v*t + 0.5*a*t^2
1 = (1.25)*t + 0.5*9.81*t^2
0 = -1 + 1.25t + 4.905t^2

Applying completing the square, we get
t = 0.342 s, - 0.597s

Technically, we don't have time with negative value. Thus, the answer is t = 0.342 seconds

6 0

3 years ago

The far point of an eye is 180 cm. A corrective lens is to be used to allow this eye to focus clearly on objects a great distanc

sveticcg [70]

Answer:

The focal length of this lens is f = 0.55 D

Explanation:

Given that the far point of an eye ( d )= 180 cm = 1.8 m

We know that focal length of lens is given by

$f = \frac{1}{d}$

Put the value of d in above equation we get

$f = \frac{1}{1.8} \ m^{-1}$

f = 0.55 D

Therefore the focal length of this lens is f = 0.55 D

5 0

3 years ago