For each relationship, write 2 conversion factors:

Describe the kinetic energy/ movement of the particles in plasma.

exis [7]

kinetic energy is a moving object potential energy is stored energy

8 0

3 years ago

It takes 338. kJ/mom to break a carbon-chlorine single bond. Calculate the maximum wavelength of light for which a carbon-chlori

Vesnalui [34]

Answer: The maximum wavelength of light for which a carbon-chlorine Single bond could be broken by absorbing a single photon is 354 nm

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

$E=\frac{Nhc}{\lambda}$

where,

E = energy of the light = $338kJ=338000J$ (1kJ=1000J)

N= avogadro's number

h = Planck's constant

c = speed of light

$\lambda$ = wavelength of light

$338\times 1000J=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^{8}}{\lambda}$

${\lambda}=0.354\times 10^{-6}m=354nm$ $(1nm=10^{-9}m$

Thus the maximum wavelength is 354 nm

6 0

3 years ago

A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

3 0

3 years ago

If the density of water is 1g/ml, what is the mass of 254ml of water?

Mariulka [41]

The mass of 254 mL of water is 254 g. Since the density of water is 1g/mL, we can simply multiply the density 1g/mL by 254 mL of water and get 254 g as our answer. Since mL is in the numerator and denominator, mL cancels out and we are left with g only.

8 0

3 years ago

if a volume of air occupying 12.0Lat 20celsius is heated to a new temperature of 100 celsius,what would be the new volume

emmasim [6.3K]

Answer:

V₂ = 15.3

Explanation:

Given data:

Initial volume = 12.0 L

Initial temperature = 20°C

Final temperature =100°C

Final volume = ?

Solution:

First of all we will convert the temperature into kelvin.

20°C + 273 = 293 K

100°C + 273 = 373 K

Formula:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 12.0 L × 373 K / 293 k

V₂ = 4476 L.K /293 k

V₂ = 15.3

V₂ = 1566 L.K / 298 K

V₂ = 5.3 L

6 0

3 years ago