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3 years ago

How strongly the planet you're on Pulls on you

Physics

2 answers:

garik1379 [7]3 years ago

6 0

The mass is very heavy compared to the moon so the weight is pushing u down 18 lb

astra-53 [7]3 years ago

5 0

The two equal and opposite forces that attract you and the
planet you're on toward each other are caused by gravity.

The force that pulls you toward the planet is what we call
your "weight".

The force that pulls the planet toward you is equal to your
weight. Nobody ever talks about that one.

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A 125 W motor accelerates a block along a level, frictionless surface at an average speed of 5.0

Lelu [443]

Answer:

25N

Explanation:

Given parameters:

Power of the motor = 125W

Average speed = 5m/s

Unknown:

Force supplied to the motor = ?

Solution:

Work done is the force applied to move a body through a particular distance;

Work done = Force x distance

Also,

Work done = Power x time

So;

Force x distance = Power x time

since force is the unknown;

Force = $\frac{Power x time}{distance}$

Speed = $\frac{distance }{time}$

Force = $\frac{Power}{speed}$

Now solve;

Force = $\frac{125}{5}$ = 25N

3 0

3 years ago

With what minimum speed must you toss a 130 gg ball straight up to just touch the 15-mm-high roof of the gymnasium if you releas

xxTIMURxx [149]

Answer:

The initial velocity is 0.5114 m/s or 511.4 mm/s

Explanation:

Let the initial velocity be 'v'.

Given:

Mass of the ball (m) = 130 g = 0.130 kg [ 1 g = 0.001 kg]

Initial height of the ball (h₁) = 1.4 mm = 0.0014 m [ 1 mm = 0.001 m]

Final height of the ball (h₂) = 15 mm = 0.015 m

Now, from conservation of energy principle, energy can neither be created nor be destroyed but converted from one form to another.

Here, the kinetic energy of the ball is converted to gravitational potential energy of the ball after reaching the final height.

Change in kinetic energy is given as:

$\Delta KE=\frac{1}{2}m(v_f^2-v_i^2)\\Where\ v_f\to Final\ velocity\\v_i\to Initial\ velocity$

As it just touches the 15 mm high roof, the final velocity will be zero. So,

$v_f=0\ m/s$ .

Now, the change in kinetic energy is equal to:

$\Delta KE = \frac{1}{2}\times 0.130\times v^2\\\\\Delta KE = 0.065v^2$

Change in gravitational potential energy = Final PE - Initial PE

So,

$\Delta U=mg(h_f-h_i)\\\\\Delta U=0.130\times 9.8\times (0.015-0.0014)\\\\\Delta U=0.017\ J$ [ g = 9.8 m/s²]

Now, Change in KE = Change in PE

$0.065v^2=0.017\\\\v=\sqrt{\frac{0.017}{0.065}}\\\\v=0.5114\ m/s\\\\1\ m=1000\ mm\\\\So,0.5114\ m=511.4\ mm\\\\\therefore v=511.4\ mm/s$

Therefore, the initial velocity is 0.5114 m/s or 511.4 mm/s

4 0

3 years ago

What are two ways in which all types of precipitation are alike

Digiron [165]

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7 0

3 years ago

What is needed to set a body in motion

kumpel [21]

Answer:

Newtons law

Explanation:

According to this law, a body at rest tends to stay at rest, and a body in motion tends to stay in motion, unless acted on by a net external force.

3 0

3 years ago

What happens to energy and frequency of a wave if its wavelength increases?

Dahasolnce [82]

Answer:

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7 0

3 years ago