All categories

3 years ago

How strongly the planet you're on Pulls on you

Physics

2 answers:

garik1379 [7]3 years ago

6 0

The mass is very heavy compared to the moon so the weight is pushing u down 18 lb

astra-53 [7]3 years ago

5 0

The two equal and opposite forces that attract you and the
planet you're on toward each other are caused by gravity.

The force that pulls you toward the planet is what we call
your "weight".

The force that pulls the planet toward you is equal to your
weight. Nobody ever talks about that one.

You might be interested in

A car has wheels of radius of 0.380 m and they rotate once every 0.100 s. What is the linear velocity of the wheels? (Units = m/

quester [9]

Answer:

v = 23.87 m/s

Explanation:

Given that,

The radius of wheels, r = 0.380 m

The wheels rotate once every 0.1 s

We need to find the linear velocity of the wheels. The linear velocity of a wheel is given by :

$v=\dfrac{2\pi r}{t}\\\\=\dfrac{2\pi \times 0.38}{0.1}\\\\=23.87\ m/s$

So, the required linear velocity of the wheel is equal to 23.87 m/s.

6 0

2 years ago

Read 2 more answers

Samara stands on the ground. Gravity is applying a force to pull her body to the ground while the ground is applying the same am

Ierofanga [76]

Mhm nice question gimmie a sec

8 0

2 years ago

A 5kg object accelerates from 3m/s to 7m/s in 5 seconds. Calculate the force required

Ad libitum [116K]

Answer:

Explanation:

a = (7-3)/5 = 0.8m/s^2

F = ma = (5)(0.8) = 4 Newtons

3 0

3 years ago

A force of 6.0 N gives a 2.0 kg block an acceleration of 3.0

Semenov [28]

Explanation:

The Net Force of the object can be written by:

Fnet = ma

where m is the mass of the object in kg

a is the acceleration of the object in m/s^2

Hence by applying the formula we get:

Fnet = (2.0)(3.0)

= 6N

We also know that Net force is also the sum of all forces acting on an object. In this case Friction and the Pushing Force is acting on the object. Hence we can write that:

Fnet = Pushing Force + (-Friction)

6N = 6N - Friction

Friction = 0N

Hence the force of friction is 0N.

7 0

3 years ago

What are the horizontal and vertical components of a lizard’s displacement if it has climbed 7m directly up a tree?

madam [21]

Answer:

The horizontal component is zero.

The vertical component is $7\sin\theta$