What is the magnitude of fs on an object lying on a flat surface without moving, on
1 answer:
The magnitude of the force acting on the object lying on a flat surface without moving is 10 N.
The given parameters;
- magnitude of force on the object, F = 10 N
- angle between the object and the horizontal flat surface = 0⁰
Apply Newton's second law of motion to determine the magnitude of the force on the object.
Due to the position of the object, the magnitude of the force acting on it is calculated as;
Therefore, the magnitude of the force acting on the object is 10 N.
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Answer:
a) E = 1.06 10⁻¹⁹ J, b) v = 9.78 10⁵ m / s
Explanation:
The physical magnitudes can be given in several units, but in general all must be reduced to the same system in a given exercise, the most used system is the international (SI)
1 eV =q V= 1.6 10⁻¹⁹ J
let's reduce the quantities requested
a) E = 1.0 eV to Joule
E = 1.0 eV (1.6 10⁻¹⁹ J / 1 eV)
E = 1.06 10⁻¹⁹ J
b) the kinetic energy is given by
K = ½ m v²
v =
the mass of the proton is
m = 1,673 10⁻²⁷ kg
let's reduce the energy to the SI system
E = 5000 ev (1.6 10-19 J / 1 eV) = 8000 10⁻¹⁹ J
let's calculate
v =
v =
v = 9.78 10⁵ m / s
Answer:
a) The distance of the object from the center of the Earth is 8.92x10⁶ m.
b) The initial acceleration of the object is 5 m/s².
Explanation:
a) The distance can be found using the equation of gravitational force:
Where:
G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²
M: is the Earth's mass = 5.97x10²⁴ kg
m: is the object's mass = 0.4 kg
F: is the force or the weight = 2.0 N
r: is the distance =?
The distance is:
Hence, the distance of the object from the center of the Earth is 8.92x10⁶ m.
b) The initial acceleration of the object can be calculated knowing the weight:
Where:
W: is the weight = 2 N
a: is the initial acceleration =?
Therefore, the initial acceleration of the object is 5 m/s².
I hope it helps you!