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34kurt
3 years ago
9

Is a personal trainer considered a doctor?

Physics
1 answer:
Temka [501]3 years ago
4 0
No, personal trainers and doctors have very different careers. Though they both do well for the body and health.
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According to Newton's third law, which describes what happens when a 4.5 kg pumpkin is launched from a catapult with a force of
max2010maxim [7]
3. Law: Every action has a reaction equal in magnitude and opposite in direction.
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3 years ago
Cliff divers at Acapulco jump into the sea from a cliff 37.1 m high. At the level of the sea, a rock sticks out a horizontal dis
Stella [2.4K]

Answer:

v_x = 4.87 m/s

Explanation:

Height of the cliff is given as

h = 37.1 m

now the time taken by the diver to hit the surface is given as

h = \frac{1}{2}gt^2

37.1 = \frac{1}{2}(9.8)t^2

t = 2.75 s

Now in the same time it has to cover a distance of 13.39 m

so the speed in horizontal direction is given as

v_x = \frac{x}{t}

v_x = \frac{13.39}{2.75}

v_x = 4.87 m/s

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4 years ago
If there was an unusually windy month, one might anticipate
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Is there multiple answer choices?
8 0
3 years ago
Two thousand two hundred frequent business travelers are asked which midwestern city they prefer: Indianapolis, Saint Louis, Chi
drek231 [11]
Frequency Table
City                       Frequency
Indianapolis              124
Saint Louis                416
Chicago                  1,225
Milwaukee                 435

Relative Frequency Table
City                            Relative Frequency
Indianapolis              124/2200 = 31/550
Saint Louis                416/2200 = 52/275
Chicago                  1,225/2200 = 49/88
Milwaukee                 435/2200 = 87/440
5 0
3 years ago
A positively charged particle initially at rest on the ground accelerated upward to 100m/s in 2.00s. If the particle has a charg
VashaNatasha [74]

Answer:

Explanation:

From the question we are told that

     The initial velocity is  u  =  100 m/s

       The time taken is  t = 2.0 s

       The charge to mass ratio is  Q/m  =  0.100 C/kg

       

Generally the acceleration is mathematically evaluated as

              a  =   \frac{u}{t }

substituting values  

               a =   \frac{100}{2}

                a =  50 \ m/s^2

The electric field is mathematical represented as

             E = \frac{(a+g)}{Q/m}

substituting values

              E = \frac{(50+9.8)}{0.100}

              E = 598 \ N/C

4 0
3 years ago
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