<u>Answer:</u>
The correct answer option is 1.6 atm.
<u>Explanation:</u>
We know that there is a sample gas which has a volume of 2.4 L with a pressure 1.2 atm and we are to find the pressure of the same gas sample if its volume is reduced to 1.8 L at a constant temperature.
We will apply the Boyle's law here which states that the "pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature".
<em>
</em>
Substituting the values in the formula to get:

Therefore, the pressure of the same gas sample will be 1.6 atm if the volume is reduced to 1.8 L at a constant temperature.
It can be in either state.....
Answer:
0.0611M of HNO3
Explanation:
<em>The concentration of the NaOH solution must be 0.1198M</em>
<em />
The reaction of NaOH with HNO3 is:
NaOH + HNO3 → NaNO3 + H2O
<em>1 mole of NaOH reacts per mole of HNO3.</em>
That means the moles of NaOH used in the titration are equal to moles of HNO3.
<em>Moles HNO3:</em>
12.75mL = 0.01275L * (0.1198mol / L) = 0.0015274 moles NaOH = Moles HNO3.
In 25.00mL = 0.025L -The volume of the aliquot-:
0.00153 moles HNO3 / 0.025L =
<h3> 0.0611M of HNO3</h3>