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Otrada [13]
3 years ago
7

What is the volume of an object whose dimensions are 5.54 cm, 10.6 cm, and 199 cm? Round your answer to the correct number of si

gnificant figures.
Chemistry
2 answers:
liubo4ka [24]3 years ago
8 0
Given your dimensions I assume you're object is rectangular.

Volume is given by length x width x height

Volume = 5.54 cm x 10.6 cm x 199cm = <span>11686.076 cm^3 (cm cubed)</span>

Since there are 3 sig figs in all three dimensions given, and you are performing multiplication only, the answer should have 3 sig figs. You can either put it in scientific notation:

1.17 x 10^4 cm^3

or

11.7 litres


ddd [48]3 years ago
7 0

Answer:

1.16\times 10^{4} cm^3 is the volume of an object.

Explanation:

Object given with the with of following dimensions are is of cuboid.

Length of object = l = 5.54 cm

Breadth of object = b= 10.6 cm

Height of object = h =199 cm

Volume of the cuboid = l × b × h

Volume of the object:

5.54 cm\times 10.6 cm\times 199 cm=11,686.76 cm^3=1.16\times 10^{4} cm^3

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4 0
2 years ago
In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol). Calculate the number of moles of chl
Annette [7]

Answer:

3.67 mol Cl

Explanation:

We need to convert g of Cl 2 to moles of Cl. First we divide 130 gCl2  by the molar mass (70.90 gCl2/mol) to find out how many moles of Cl2 do we have.

130 gCl2 x \frac{1 mol Cl2 }{70.90 gCl2} = 1.83 mol Cl2

Then we need to convert 1.83 mol de Cl2 to moles of Cl. We have 2 moles of Cl in every Cl2 molecule so we just need to multiply by 2.

1.83 molCl2 x \frac{2 molCl}{1 molCl2} = 3.67 molCl

8 0
3 years ago
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ascorbic acid is a diprotic acid (Ka= 8.0x10^-5 and Ka2= 1.6x10^-12). What is the pH of a 0.260 M solution of ascorbic acid
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The pH of a 0.260 M solution of ascorbic acid is 0.585. Details about pH can be found below.

<h3>How to calculate pH?</h3>

The pH of a solution can be calculated using the following expression:

pH = - log {H+}

According to this question, ascorbic acid is a diprotic acid and posseses a concentration of 0.260M. The pH can be calculated as follows;

pH = - log {0.260}

pH = 0.585

Therefore, the pH of a 0.260 M solution of ascorbic acid is 0.585.

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2 years ago
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3 years ago
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All chemical reactions obey this law of conservation.

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