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2 years ago

Is thiamine mononitrate an ionic bond or covalent bond?

Chemistry

2 answers:

timofeeve [1]2 years ago

7 0

It is a covalent bond. Whenever a compound uses such suffixes like mono, di, tri, tetra, and so on, it is a covalent compound- thus having covalent bonds.

faust18 [17]2 years ago

5 0

Answer:

It's a covalent bond

Explanation:

The diference of electronegativity between the two atoms bonding can help you to decide if a bond is either covalent or ionic.

As shown in the figure, the oxygen atoms of the nitrate (left) will interact with the nitrogen atom of the thiamine(right).

The oxygen have an electronegativity of 3.5 (one of the most electronegative elements) and the nitrogen a 3.0

Being the difference: 3.5 - 3.0=0.5

Now, how this helps to decide the type of bond? For covalent bonds it's expected to have a electronegativity diffetence of < 1.5. On the other hand, for ionic bonds this value should be > 1.5

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Misha Larkins [42]

Explanation:

Let the volume of the solution be 100 ml.

As the volume of glycol = 50 = volume of water

Hence, the number of moles of glycol = $\frac{mass}{molar mass}$

= $\frac{density \times volume}{molar mass}$

= $\frac{1.1088 \times 50}{62 g/mol}$

= 0.894 mol

Hence, number of moles of water = $\frac{50 \times 0.998}{18}$

= 2.77

As glycol is dissolved in water.

So, the molality = $0.894 \times \frac{1000}{49.92}$

= 17.9

Therefore, the expected freezing point = $-1.86 \times 17.9$

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Thus, we can conclude that the expected freezing point is $-33.31^{o}C$ .

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2 years ago

A company is testing drinking water and wants to ensure that ca content is below 155 ppm. What is the maximum amount of Ca that

BabaBlast [244]

Answer:

138 mg

Explanation:

A company is testing drinking water and wants to ensure that Ca content is below 155 ppm (= 155 mg/kg), that is, 155 milligrams of calcium per kilogram of drinking water. We need to find the maximum amount of calcium in 890 g of drinking water.

Step 1: Convert the mass of drinking water to kilograms.

We will use the relation 1 kg = 1000 g.

$890g \times \frac{1kg}{1000g} =0.890kg$

Step 2: Calculate the maximum amount of calcium in 0.890 kg of drinking water

$0.890gH_2O \times \frac{155mgCa}{1kgH_2O} = 138mgCa$

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