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swat32
3 years ago
14

Is thiamine mononitrate an ionic bond or covalent bond?

Chemistry
2 answers:
timofeeve [1]3 years ago
7 0
It is a covalent bond. Whenever a compound uses such suffixes like mono, di, tri, tetra, and so on, it is a covalent compound- thus having covalent bonds.
faust18 [17]3 years ago
5 0

Answer:

It's a <u>covalent bond</u>

Explanation:

The diference of electronegativity between the two atoms bonding can help you to decide if a bond is either <u>covalent</u> or <u>ionic</u>.

As shown in the figure, the oxygen atoms of the nitrate (left) will interact with the nitrogen atom of the thiamine(right).

The oxygen have an electronegativity of 3.5 (one of the most electronegative elements) and the nitrogen a 3.0

Being the difference: 3.5 - 3.0=0.5

Now, how this helps to decide the type of bond? For covalent bonds it's expected to have a electronegativity diffetence of < 1.5. On the other hand, for ionic bonds this value should be > 1.5

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almond37 [142]

Answer:

CH₄(g)  +  2O₂(g) → CO₂(g)  +  2H₂O(l)

Mole ratios for the balanced equation be:

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Explanation:

CH4(g)+O2(g) → CO2(g)+ H2O(l)

To balance a chemical equation, you must have the same mole of each element in both sides of the reaction (reactant side and product side)

CH₄(g)  +  2O₂(g) → CO₂(g)  +  2H₂O(l)

2 C

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8 O

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It takes 1 mole of methane to react with 2 mole of oxygen in order to produce 1 mol of dioxide and 2 mole of water.

Mole ratios for the balanced equation be:

Mole ratios for the balanced equation be:

1:2, 2:1, 1:1, 1:2, 2:2  - We should compare each compound

1 mol methane → 2 mole of oxygen

2 mole of oxygen → 1 mol of methane

2 mole of oxygen → 1 mol of dioxide

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2 mole of water → 2 mole of oxygen (the same as opposite)

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Rolls of foil are 304 mmmm wide and 0.014 mmmm thick. (The density of foil is 2.7 g/cm3g/cm3 .) What maximum length of foil can
ratelena [41]

Answer:

92.2 m

Explanation:

Given that:=

The breadth = 304 mm

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Let Length = x mm

Volume = Length\times breadth\times height

Thus,

Volume = 304\times 0.014\times x\ mm^3=4.256x\ mm^3

Also, 1 mm³ = 0.001 cm³

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Given that density = 2.7 g/cm³

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So,

Volume=\frac{Mass}{Density}=\frac{1060}{2.7}\ cm^3=392.59\ cm^3

So,

0.004256*x = 392.59

x = 92243.89 mm

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