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swat32
2 years ago
14

Is thiamine mononitrate an ionic bond or covalent bond?

Chemistry
2 answers:
timofeeve [1]2 years ago
7 0
It is a covalent bond. Whenever a compound uses such suffixes like mono, di, tri, tetra, and so on, it is a covalent compound- thus having covalent bonds.
faust18 [17]2 years ago
5 0

Answer:

It's a <u>covalent bond</u>

Explanation:

The diference of electronegativity between the two atoms bonding can help you to decide if a bond is either <u>covalent</u> or <u>ionic</u>.

As shown in the figure, the oxygen atoms of the nitrate (left) will interact with the nitrogen atom of the thiamine(right).

The oxygen have an electronegativity of 3.5 (one of the most electronegative elements) and the nitrogen a 3.0

Being the difference: 3.5 - 3.0=0.5

Now, how this helps to decide the type of bond? For covalent bonds it's expected to have a electronegativity diffetence of < 1.5. On the other hand, for ionic bonds this value should be > 1.5

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They stay the same

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True or False: You can make a concentrated solution more dilute by adding solvent.
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6 0
2 years ago
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The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

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Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

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Change in temperature of the calorimeter = ΔT = 2.053°C

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15,066.8 J=C\times 2.053^oC

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Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = \frac{2.900 g}{180.16 g/mol}=0.016097 mol

Energy released by the 0.016097 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
2 years ago
How do atoms and molecules of elements and compounds combine in chemical reactions?
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Answer:

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8 0
2 years ago
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Arturiano [62]
<h3><u>Answer;</u></h3>

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3 years ago
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