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maks197457 [2]
3 years ago
8

1 . A farmer moves along the boundary of his rectangular field of side 10m x 20m . farmer covers 1m in 1sec . what will be the m

agnitude of displacement at the total distance travelled.
2 . Rahul pedals his cycle from rest. Pedals his cycle to get a
velocity of 10 ms-1  in 30 seconds.
then he applies brakes in such that the velocity of the cycle comes does to 6
ms-1  in next 5 seconds . calculate
the acceleration and deceleration .
Physics
1 answer:
SSSSS [86.1K]3 years ago
8 0
1). He's walking the 'perimeter' of his field, meaning 'the distance all the way around'.
If he stays right along the fence all the way, then the total distance he walks is
(10 + 20 + 10 + 20) = 60 meters. (It's a small field ... about 5% of an acre.)
The magnitude of displacement is the distance between the start point and end point,
regardless of the route.  After he finishes one whole trip around, his displacement is
zero, because he ends up at the same place where he started.
Notice the big fat red herring in the question: None of this depends on the speed
at which he walks.

2).  Acceleration = (change in speed) / (time for the change)

While speeding up, acceleration = (10 - 0) / 30 = 1/3 meter per second².

While slowing down, deceleration = (6 - 10) / 5 = -4/5 = -0.8 meter per second²

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At an accident scene on a level road, investigators measure a car’s skid mark to be 88 m long. The accident occurred on a rainy
Oduvanchick [21]

Answer:

The the speed of the car is 26.91 m/s.

Explanation:

Given that,

distance d = 88 m

Kinetic friction = 0.42

We need to calculate the the speed of the car

Using  the work-energy principle

work done = change in kinetic energy

W=\Delta K.E

\mu\ mg\times d=\dfrac{1}{2}mv^2

v^2=2\mu g d

Put the value into the formula

v=\sqrt{2\times0.42\times9.8\times88}

v=26.91\ m/s

Hence, The the speed of the car is 26.91 m/s.

3 0
3 years ago
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Which type of graph is best suited to show the breakdown of how this teacher weights each category ?
MArishka [77]

Answer:

pie graph?

Explanation:

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3 In a television tube, an electron starting from rest experiences a force of 4.0 × 10−15 N over a distance of 50 cm. The final
MAXImum [283]

Answer:

The final speed of the electron = 2.095×10⁸ m/s

Explanation:

From newton's fundamental equation of dynamics,

F = ma ........................Equation 1

Where F = force, m = mass of the electron, a = acceleration of the electron.

making a the subject of the equation,

a = F/m.................... Equation 2

Given: F = 4.0×10⁻¹⁵ N,

Constant: m =  9.109×10⁻³¹ kg.

Substituting into equation 2

a = 4.0×10⁻¹⁵/9.109×10⁻³¹

a = 4.39×10¹⁶ m/s².

Using newton's equation of motion,

v² = u²+2as .......................... Equation 3

Where v = final velocity of the electron, u = initial velocity of the electron, a = acceleration of the electron, s = distance covered by the electron.

Given: u = 0 m/s(at rest), s = 50 cm = 0.5 m, a = 4.39×10¹⁶ m/s²

Substituting into equation 3

v² = 0² + 2(0.5)(4.39×10¹⁶)

v = √(4.39×10¹⁶)

v = 2.095×10⁸ m/s

Thus the final speed of the electron = 2.095×10⁸ m/s

7 0
3 years ago
A boy pushes forward a cart of groceries with a total mass of 40.0 kg. What is the acceleration of the cart if the net force on
melisa1 [442]

1.5m/s2

F=ma

a=F/m

a=60/40

a=1.5m/s2

6 0
3 years ago
Complete the equation???
soldi70 [24.7K]

Here in nuclear reaction we can say that sum of neutrons and protons in reactant side and product side will be same always

Here mass number on the product side is given to us

so sum of mass number is given as

A_1 + A_2 = 265 + 1 = 266

now on the reactant side also the number must be same

A_1' + A_2' = 58 + x

now we will have

58 + x = 266

x = 208

Now number of protons on product side is given as

P_1 + P_2 = 108 + 0

now we also know that atomic number of Fe is 26

so now we will have

P_1' + P_2' = 108

26 + P_2' = 108

P_2' = 82

now the equation is given as

_{26}^{58}Fe + _{82}^{208}Pb = _{108}^{266}Hs + _0^1X

8 0
3 years ago
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