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hram777 [196]
3 years ago
14

What is shearing? is it means taking out the hair of the sheep

Physics
2 answers:
timama [110]3 years ago
8 0

Answer:

The act or operation of clipping with shears or a shearing machine, as the wool from sheep, or the nap from cloth.

Explanation:

ICE Princess25 [194]3 years ago
5 0

Answer:

Thats  a greate quiestionm look it up

Explanation:

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Determine for which class of lever the output force is always greater than the input force. for which class is the output force
umka2103 [35]
The 3rd class lever is the <span>output force always less than the input force, becuase its mechanical advantage is always less than 1. this also due that in a 3rd class lever the effort arm is shorter than the load arm, that is why the output is lower than the input force. but 3rd class lever is a speed multiplier lever</span>
5 0
4 years ago
Read 2 more answers
Is it possible to accelerate and not speed up or slow down?
Sergeeva-Olga [200]

Answer: No,

explanation: When the object is<u> neither</u> <em>speeding up or slowing down</em>, we can say that its speed is <u><em>constant</em></u>.

Hope this helps

Plz mark brainlesit

5 0
3 years ago
A hydraulic lift raises a 4000 kg automobile when a 500N force is applied to the smaller piston. If the smaller piston has an ar
MariettaO [177]

Answer:

The cross-sectional area of the larger piston is 800 cm².

Explanation:

Given;

mass of the automobile, m = 4000 kg

force applied on the small piston, F₁ = 500 N

area of the smaller piston, A₁ = 10 cm²

load lifted by the larger piston, F₂ = 4000 x 10 = 40,000 N

Pressure experienced by each piston is given as;

\frac{F_1}{A_1} = \frac{F_2}{A_2}

Where;

A₂ is the cross-sectional area of the larger piston

\frac{F_1}{A_1} = \frac{F_2}{A_2} \\\\A_2 = \frac{F_2A_1}{F_1} \\\\A_2 = \frac{40,000 \ \times\ 10}{500} \\\\A_2=800 \ cm^2

Therefore, the cross-sectional area of the larger piston is 800 cm².

8 0
3 years ago
A 21.0 kg shopping cart is moving with a velocity of 4.0 m / s. It strikes a 7.0 kg box that is initially at rest. They stick to
jonny [76]

Explanation:

Given that,

Mass of the shopping cart, m_s=21\ kg

Initial speed of the shopping cart, u_s=4\ m/s

Mass of the box, m_b=7\ kg

Initial speed of the box, u_b=0 (at rest)

They stick together and continue moving at a new velocity. It is a case of inelastic collision.

(a) The momentum of the shopping cart before the collision is given by :

p_s=m_s\times u_s\\\\p_s=21\times 4\\\\p_s=84\ kg-m/s

(b) The momentum of the box before the collision is given by :

p_b=m_b\times u_b\\\\p_b=7\times 0\\\\p_b=0

(c) The velocity of the combined shopping cart/box wreckage after the collision is given by using the conservation of momentum as :

m_su_s+m_bu_b=(m_s+m_b)V\\\\V=\dfrac{m_su_s+m_bu_b}{(m_s+m_b)}\\\\V=\dfrac{21\times 4+0}{(21+7)}\\\\V=3\ m/s

Hence, this is the required solution.

8 0
3 years ago
True or False
jasenka [17]
False . accelerating means to increase but moving at a constant speed means you stay the same .
6 0
3 years ago
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