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Otrada [13]
3 years ago
7

The tsunami described in the passage produced a very erratic pattern of damage, with some areas seeing very large waves and near

by areas seeing only small waves. Which of the following is a possible explanation?
A. Certain areas saw the wave from the primary source, others only the reflected waves.
B. The superposition of waves from the primary source and reflected waves produced regions of constructive and destructive interference.
C. A tsunami is a standing wave, and certain locations were at nodal positions, others at antinodal positions.
Physics
1 answer:
Lunna [17]3 years ago
5 0

Answer:B. The superposition of waves from the primary source and reflected waves produced regions of constructive and destructive interference.

Explanation: Tsunami is described as several waves originating from a water body mainly an ocean caused by Large scale earth movements taking place under the sea.

Superimposition of wave is the movement of one wave on another,it can be constructive or destructive.

Constructive interference is a wave interference that take place causing the Crest of one wave to align with that of another wave leading to high amplitude.

Destructive interference is a wave interference that take place causing the Trouph of one wave to align with the crest of another wave leading to low amplitude wave.

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<h3>What is pressure?</h3>

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4 0
1 year ago
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4 0
3 years ago
Which statement correctly explains scientific theories?
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4 0
3 years ago
Read 2 more answers
** URGENT** The voltage across the primary winding is 350,000 V, and the voltage across the secondary winding is 17,500 V. If th
Vlad [161]

As we know that in transformers we have

\frac{V_s}{V_p} = \frac{N_s}{N_p}

here we know that

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now from above equation we will have

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6 0
3 years ago
In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these s
riadik2000 [5.3K]

Answer:

Part a)

\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}

Part b)

\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}

Explanation:

As we know that the see saw bar is massless so here torque due to two masses is given as

\tau = I\alpha

here we will have

\tau = (m_1g - m_2g)(\frac{L}{2})

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Part b)

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so we will have

I = (m_1 + m_2)\frac{L^2}{4} + \frac{m_{bar}L^2}{12}

now the acceleration is given as

\alpha = \frac{\tau}{I}

\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}

7 0
3 years ago
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