Answer:
D) The heavier ball will have a higher temperature because the change of temperature is inversely proportional to mass.
Explanation:
As stated in the problem, the amount of heat released by each ball is
where
m is the mass of the ball
Cp is the specific heat of iron (so, it is equal for both balls)
is the change in temperature of each ball
In this problem, we are said that the amount of heat released by the two balls, Q, is the same. Cp is also the same: this means that the product 
must be the same for the two balls. So, the mass and the change in temperature are inversely proportional: therefore, the heavier ball will have a smaller change in temperature. And since both balls starts from the same temperature, 100 C, this means that the heavier ball will reach a higher temperature than the lighter ball.
Big band is music group (a group of people who perform instrumental and/or vocal music ) playing jazz or jazz-influenced popular music and which was popular during the Swing Era from the mid-1930s until the late 1940s. These big bands contained saxophones, trumpets, trombone and other instruments and typically consisted of approximately 12 to 25 musicians.
It takes 2 years of graduate study in a subfeild, practicum experience, and a thesis.
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The definition of speed is (distance covered) / (time to cover the distance) .
So a unit of speed has to be (a unit of length) / (a unit of time) .
Here are several perfectly fine units of speed:
-- miles per hour
-- feet per second
-- meters per second
-- kilometers per hour
-- inches per second
-- centimeters per minute
-- yards per Century
-- furlongs per fortnight
-- nanometers per microsecond
-- Smoots per week
-- parsecs per millenium
Answer:
θ=108rad
t =10.29seconds
α=-8.17rad/s²
Explanation:
Given that
At t=0, Wo=24rad/sec
Constant angular acceleration =30rad/s²
At t=2, θ=432rad as it try to stop because the circuit break
Angular motion
W=Wo+αt
θ=Wot+1/2αt²
W²=Wo²+2αθ
We need to find θ between 0sec to 2sec when the wheel stop
a. θ=Wot+1/2αt²
θ=24×2+1/2×30×2²
θ=48+60
θ=108rad.
b. W=Wo+αt
W=24+30×2
W=84rad/s
This is the final angular velocity which is the initial angular velocity when the wheel starts to decelerate.
Wo=84rad/sec
W=0rad/s, because the wheel stop at θ=432rad
Using W²=Wo²+2αθ
0²=84²+2×α×432
-84²=864α
α=-8.17rad/s²
It is negative because it is decelerating
Now, time taken for the wheel to stop
W=Wo+αt
0=84-8.17t
-84=-8.17t
Then t =10.29seconds.
a. θ=108rad
b. t =10.29seconds
c. α=-8.17rad/s²
