Use the law of conservation of momentum to solve this problem. We have a system of two bodies (bullet and block). Initially, only the bullet has a non-zero momentum. After the collision, both have some momentum and we know the part for the bullet, so it is simple to isolate the part for the block. Call v_t0 the initial bullet speed, v_t1 new bullet speed, v_k speed of block. (similarly for masses):
The block will move with a speed of 2 m/s in the direction of the bullet.
Answer:
1) herbivors
2) members of the same species living in the same place at the same time
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Answer:
The protons and the neutron are located in the nucleus and the electrons is the outermost region
Answer:
A)Explanation:
Let object distance be u.
Image distance v = 1.06 - u
Focal length = 20 cm = .2 m
Applying lens formula
1 / v - 1 / u = 1 / f
1 /( 1.06-u) - 1 / u = 1 / .2
5 u² -3.3u - 1.06 =0
It will have two roots
u₁ = .1636 m, u₂ = .8964 m
B ) Magnification
= u = .1636m , v = .8964m
m = .8964 / .1636 = 5.48
C ) When u = .8964m ,v = .1634m
m = .1634 / .8964
=.182
Answer:
Torque=13798.4 N.m
Explanation:
Given data
Mass of beam m₁=500 kg
Mass of the person m₂=70 kg
length of steel r₁=4.40m
center of gravity of the beam is at r₂=r₁/2 =4.40/2 = 2.20m
To find
Torque
Solution
Torque due to beam own weight
Torque due to person
Now for total torque
