Answer:
![[F]=[MLT^{-2}]](https://tex.z-dn.net/?f=%5BF%5D%3D%5BMLT%5E%7B-2%7D%5D)
Explanation:
Newton’s second law states that the acceleration a of an object is proportional to the force F acting on it is inversely proportional to its mass m. The mathematical expression for the second law of motion is given by :
F = m × a
F is the applied force
m is the mass of the object
a is the acceleration due to gravity
We need to find the dimensions of force. The dimension of force m and a are as follows :
![[m]=[M]](https://tex.z-dn.net/?f=%5Bm%5D%3D%5BM%5D)
![[a]=[LT^{-2}]](https://tex.z-dn.net/?f=%5Ba%5D%3D%5BLT%5E%7B-2%7D%5D)
So, the dimension of force F is,
. Hence, this is the required solution.
Answer:
acceleration = 2.4525 m/s²
Explanation:
Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²
Tension in the rope = T
Sol: m2 > m1
i) for downward motion of m2:
m2 a = m2 g - T
5 a = 5 × 9.81 m/s² - T
⇒ T = 49.05 m/s² - 5 a Eqn (a)
ii) for upward motion of m1
m a = T - m1 g
3 a = T - 3 × 9.8 m/s²
⇒ T = 3 a + 29.43 m/s² Eqn (b)
Equating Eqn (a) and(b)
49.05 m/s² - 5 a = T = 3 a + 29.43 m/s²
49.05 m/s² - 29.43 m/s² = 3 a + 5 a
19.62 m/s² = 8 a
⇒ a = 2.4525 m/s²
Answer:
Explanation:
Un motor aeronáutico o motor de aviación es aquel que se utiliza para la propulsión de aeronaves mediante la generación de una fuerza de arrastre.
Existen distintos tipos de motores de aviación, aunque se dividen en dos clases básicas: motores recíprocos —o de pistón— y de turbina de gas. Recientemente y gracias al desarrollo de la NASA y otras entidades, se ha comenzado también la producción de motores eléctricos para aeronaves que funcionen con energía solar fotovoltaica.
eso depende de el motor que cada avion tenga
The naturally occurring radioisotope which is used as the fuel for a nuclear reactor is the Uranium-235. It has been said that one kilogram of Uranium-235 can theoretically male about 20 terajoules of energy when used as a fuel for power plants.
Answer:
after t = 3 hours compound A remain 0.396 M
t = 12.98 hours
Explanation:
P = P_0*e^(-kt)
t = 30 minutes = 30/60 hours = 0.5 hours
and P_0 = 0.60M
and P after t = 0.5 hours is 0.56 M
(0.56/0.6) = e^(-kt)
0.933 =e^(-kt)
k = 0.138
P = P_0*e^(-0.138t)
Now after t = 3 hours,
P = 0.6* e^((-0.138)*3) = 0.396 M
time when P = 0.1 M
0.1 = 0.6*e^(-0.138t)
t = 12.98 hours