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pishuonlain [190]
3 years ago
11

6) Why do electromagnetic waves not require a medium for travel?

Physics
1 answer:
sergij07 [2.7K]3 years ago
8 0
Electromagnetic waves are a type of
transverse wave. This wave does not
require media for travel. As the name
implies a wave, these waves indicate
electrical and magnetic properties. No
cost whatsoever happened to the wave. Electromagnetic waves work with the
laws of reflection and refraction. They
travel the straight line in a vacuum at a
speed of 3 x 108 ms-1. The intensity of
electromagnetic waves depends on the
strength of the electric field.
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Suppose that a sound has initial intensity β1 measured in decibels. This sound now increases in intensity by a factor f. What is
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Answer:

β2= β1+10*f

Explanation:

comparing β2 and β1, it is said that β2 is increased by a factor of f.

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Determine if a sentence is an argument?​
Aneli [31]

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The tone really matters and if there are any exclamation marks also.

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2 years ago
The overall length of a piccolo is 32.0 cm. The resonating air column vibrates as in a pipe that is open at both ends. (a) Find
lana66690 [7]

Answer:

lowest frequency = 535.93 Hz

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Explanation:

given data

length L = 32 cm = 0.32 m

to find out

frequency and distance between adjacent anti nodes

solution

we consider here speed of sound through air at room temperature 20 degree is  approximately  v = 343 m/s

so

lowest frequency will be = \frac{v}{2L}   ..............1

put here value in equation 1

lowest frequency will be = \frac{343}{2(0.32)}

lowest frequency = 535.93 Hz

and

we have given highest frequency f = 4000Hz

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wavelength =  \frac{343}{4000}  

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so distance =  \frac{wavelength}{2}   ..............3

distance =  \frac{0.08575}{2}  

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3 0
3 years ago
Halleys comet has period of 75.3 years. Using Kepler’s third law, find it’s semimajor axis expressed in astronomical units?
natta225 [31]

Answer: 17.83 AU

Explanation:

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T^{2}\propto a^{3}  (1)

Talking in general, this law states a relation between the <u>orbital period</u> T of a body (moon, planet, satellite, comet) orbiting a greater body in space with the <u>size</u> a of its orbit.

However, if T is measured in <u>years</u>, and a is measured in <u>astronomical units</u> (equivalent to the distance between the Sun and the Earth: 1AU=1.5(10)^{8}km), equation (1) becomes:

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This means that now both sides of the equation are equal.

Knowing T=75.3years and isolating a from (2):

a=\sqrt[3]{T^{2}}=T^{2/3}  (3)

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Finally:

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4 0
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