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pishuonlain [190]
3 years ago
11

6) Why do electromagnetic waves not require a medium for travel?

Physics
1 answer:
sergij07 [2.7K]3 years ago
8 0
Electromagnetic waves are a type of
transverse wave. This wave does not
require media for travel. As the name
implies a wave, these waves indicate
electrical and magnetic properties. No
cost whatsoever happened to the wave. Electromagnetic waves work with the
laws of reflection and refraction. They
travel the straight line in a vacuum at a
speed of 3 x 108 ms-1. The intensity of
electromagnetic waves depends on the
strength of the electric field.
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A billiard ball is dropped from a height of 64 feet. Use the position function s(t) = –16???? 2 + ????0???? + ????0 to answer th
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s(t) = -16*t^2 + 64

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Explanation:

Given:-

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Solution:-

- To determine the position function we must initialize our problem and use the given general equation.

- s(t) is the position of the billiard ball from the ground at time t. So when t = 0, then s(t) = h. Hence, we have:

                                  s(t) = s_o = h = 64 ft

- Similarly we know that v_o is the initial velocity of the ball. Since, the ball was dropped we say that the initial velocity v_o = 0. Hence, the position of the ball from ground is given by following expression:

                                  s(t) = -16*t^2 + 64  

- To find the velocity expression v(t) we will take the time derivative of the position expression s(t) as follows:

                                  v(t) = d s(t) / dt

                                  v(t) = -16*2*t + 0

                                  v(t) = -32*t ft/s

- Similarly, the expression for acceleration a(t) is given by the time derivative of the velocity expression v(t) as follows:

                                  a(t) = d v(t) / dt

                                  a(t) = -32*t

                                  a(t) = -32 ft/s^2

- The velocity of ball at impact can be determined by evaluating s(t) = 0 and find the value for time t. Then that time t can be substituted in the velocity expression v(t) for final velocity. Or we could use the following 3rd kinematic equation as follows:

                                 v(t)^2 - 0^2 = 2*a(t)*s_o

                                 v(t)^2 = 2*(32)*(64)

                                 v(t) = 64 ft/s

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