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SOVA2 [1]
3 years ago
12

Food can spoil very quickly. Which methods are used to minimize the reactions that allow bacteria and fungi to grow?

Chemistry
2 answers:
dem82 [27]3 years ago
7 0

Answer:  preservatives and low temperature

Explanation:

Oduvanchick [21]3 years ago
3 0

Answer:

preservatives and low temperature

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If two clear liquids are mixed and a precipitate formed, what has probably happened?
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It will probably turned into a gumy
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The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol. Part A If an enzyme increases the
emmasim [6.3K]

Answer:

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

Explanation:

From the given information:

The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.

In this  same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;

Rate factor in the absence of catalyst:

k_1= A*e^{^{^{ \dfrac {- Ea_1}{RT}}

Rate factor in the presence of catalyst:

k_2= A*e^{^{^{ \dfrac {- Ea_2}{RT}}

Assuming the catalyzed reaction and the uncatalyzed reaction are  taking place at the same temperature :

Then;

the ratio of the rate factors can be expressed as:

\dfrac{k_2}{k_1}={  \dfrac {e^{ \dfrac {- Ea_2}{RT} }} { e^{ \dfrac {- Ea_1}{RT} }}

\dfrac{k_2}{k_1}={  \dfrac {e^{[  Ea_1 - Ea_2 ] }}{RT} }}

Thus;

Ea_1-Ea_2 = RT In \dfrac{k_2}{k_1}

Let say the assumed temperature = 25° C

= (25+ 273)K

= 298 K

Then ;

Ea_1-Ea_2 = 8.314 \  J/mol/K * 298 \ K *  In (10^6)

Ea_1-Ea_2 = 34228.92 \ J/mol

\mathbf{Ea_1-Ea_2 = 34.23 \ kJ/mol}

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

8 0
3 years ago
O Previous
Ede4ka [16]

Answer:

what is scientific model

Explanation:

4 0
3 years ago
Which would have more mass: a mole of sodium or a mole of copper? How do you know?
bearhunter [10]

Answer:

copper

Explanation:

so for this you can work out the mass for both and compare

so mass = moles × mr

so mass of sodium = 1 × 23= 23 g

and mass of copper = 1 × 63.5= 63.5 g

so copper have more mass :)

5 0
3 years ago
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