Answer:
H2O2
Explanation:
By numbering the atoms we know about that it’s Hydrogen Peroxide
3.08*10^23 ions of Na+ and Cl- will be present in 30g of NaCl.
Weight of NaCl is equal to sum of weight of one mole of sodium and one mole of chloride.
Mathematically, it can be represented as -
1 mol (Na) + 1 mol (Cl)
= 23.0+ 35.5
= 58.5 g/mol
In 58.5 gram of NaCl, there is one mole of Na or 6.02*10^23 ions
In one gram of NaCl, there will be
=6.02*10^23/58.5 sodium ions
In 30 grams of NaCl, the number of sodium ions will be -
(6.02*10^23*30)/ 58.5
=3.08*10^23 ions
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1. ionic compound , aqueous cations and aqueous anions
2. covalent compound aqueous covalent compound
<u>Explanation:</u>
1. A(n) <u>ionic compound </u> dissolves in water , H₂O(l), will produce <u>aqueous cations </u> and <u>aqueous anions </u>in solution.
When NaCl dissolves in water it will produce Na⁺ and Cl⁻ ions in solution
2. A(n) <u>covalent compound </u> dissolves in water , H₂O(l), will produce <u>aqueous covalent compound </u>in solution.
When Ammonia (NH₃) dissolves in water it forms aqueous ammonia, NH₃(aq)
Organic compounds, like carbohydrates, proteins, nucleic acids, and lipids, are all good examples of covalent compounds.
Answer:
You need to make sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal. :)
The options in the question are:
a) +0.46 V
b) +0.617 V
c) +1.39 V
d) -0.46 V
e) +1.21 V
Answer:
b) +0.617 V
Explanation:
The equation shows that the anode is Sn2+/Sn4+ while the cathode is Fe3+/Fe2+.
The E° cell is obtained from E°cathode - E°Anode
E°cathode= 0.154V
E°Anode= 0.771V
E° cell= E°cathode - E°Anode= 0.771-0.154=0.617