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3 years ago

Why does the human eye perceive a red colored dress as the red color?

2 answers:

8 0

We have a 3-colour vision which happens to be the primary colours: red, blue and yellow. So, we can see red, and that is why we see it.

To see other we just mix the different cells as if we where mixing paint to get a new colour.

Hope it was easy to understand,

Happy homework/ study/ exam!

olga55 [171]3 years ago

4 0

Because the color red only reflects different amounts of light therefore produces a different color we see as red.

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Which of the following statements is true about the food chain below? Grass ⇒ grasshopper ⇒ bird ⇒ hawk The amount of energy tra

lorasvet [3.4K]

In a food chain we arrange the energy in the form of a pyramid.

The producers are on the base of pyramid and then consumers are towards peak.

in the given food chain grass is being eaten by grasshopper which are food of birds.

Grasshoppers are also eaten up by Hawks. so both brids and hawks are feeding upon grasshoppers thus the amount of energy transferred from the grass to the grasshopper is the same as the amount of energy transferred from the grasshopper to the bird.

8 0

3 years ago

Read 2 more answers

A sample of 211 g of iron (III) bromide is reacted with

Alisiya [41]

FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

FeBr₃

211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :

$\tt n=\dfrac{mass}{MW}\\\\n=\dfrac{211}{295,56}\\\\n=0.714$

Na₂S

186 g of Sodium sulfide(MW=78,0452 g/mol), so mol Na₂S :

$\tt n=\dfrac{186}{78.0452}=2.38$

Coefficient ratio from the equation FeBr₃ : Na₂S = 2 : 3, so mol ratio :

$\tt FeBr_3\div Na_2S=\dfrac{0.714}{2}\div \dfrac{2.38}{3}=0.357\div 0.793$

So FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

$\tt \dfrac{6}{3}\times 0.714=1.428$

6 0

3 years ago

If you have 12.5g of fluoride and 16.2g of sodium, which is the limiting reactant and how sodium fluoride in grams is your theor

Korvikt [17]

Answer:

F2 is the limiting reactant

27.6 grams of NaF is produced.

Explanation:

Balance the equation first.

2Na+ F2 ---> 2NaF

To find the limiting reactant, solve for how much NaF can be produced with Na and F2

12.5g F2 x (1 mole F2/ 38.00 grams F2)x (2 mole NaF/ 1 mole F2)

=0.658 moles NaF

16.2g Na x (1 mole Na/ 22.99 grams Na)x (2 mole NaF/ 2 mole Na)

=0.705 moles NaF

Since F2 produced the least NaF, F2 is the limiting reactant.

Now, to find how much NaF there is, use the moles solved above with F2 as the limiting reactant.

0.658 moles NaF x (41.99 grams NaF/ 1 mole NaF)= 27.6 moles NaF

27.6 moles of NaF would be theoretically produced.

8 0

3 years ago

Calculate the molarity of a solution with 233.772g sodium chloride dissolved in 2,000mL of water

LekaFEV [45]

Answer:

The molarity is 2M

Explanation:

First , we calculate the weight of 1 mol of NaCl:

Weight 1mol NaCl= Weight Na + Weight Cl= 23 g+ 35, 5 g= 58, 5 g/mol

58,5 g---1 mol NaCl

233,772 g--------x= (233,772 g x1 mol NaCl)/58,5 g= 4 mol NaCl

<em>A solution molar--> moles of solute in 1 L of solution:</em>

2 L-----4 mol NaCl

1L----x0( 1L x4mol NaCl)/4L =2moles NaCl---> 2 M

3 0

3 years ago

A redox reaction employed in an electrochemical cell has a negative . Which statement is true? a) E∘cell is positive b) K>1 E

krok68 [10]

Answer:

d. K<1 E∘cell is negative

Explanation:

Since E⁰ = negative , ΔG = -nFE⁰ = -nF -ve = +ve.

Also, ΔG = -RTlnK

K = exp(-RTΔG)

Since ΔG = +ve, -RTΔG = -ve

K = 1/exp(RTΔG) < 1.

So our answer is E⁰ cell is negative and K < 1

5 0

3 years ago