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sammy [17]
3 years ago
8

A 5.00 kg crate is on a 21.0° hill.

Physics
1 answer:
mojhsa [17]3 years ago
8 0

Answer: 4575N

Explanation:

For y component, W = mgcosø

W = 500×9.8cos21

W = 4574.54N

Find the diagram in the attached file

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LekaFEV [45]

The statement that best describes the production of energy in the Sun is nuclei with less mass combine to form nuclei with more mass in the Sun’s core and release energy.

<h3>How is energy produced in the sun?</h3>

Sun is a major source of renewable energy to the Earth. This energy serves various purposes by living organisms.

However, the energy is generated as a result of nuclear fusion, which is the combination of smaller particles to form a larger one.

Therefore, the statement that best describes the production of energy in the Sun is nuclei with less mass combine to form nuclei with more mass in the Sun’s core and release energy.

Learn more about energy at: brainly.com/question/1932868

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7 0
1 year ago
Find the coefficient of kinetic friction μk. express your answer in terms of some or all of the variables d1, d2, and θ.
Andre45 [30]
<span>internet tension = mass * acceleration internet tension = 23 – Friction tension = 14 * acceleration Friction tension = µ * 14 * 9.8 = µ * 137.2 23 – µ * 137.2 = 14 * acceleration Distance = undemanding speed * time undemanding speed = ½ * (preliminary speed + very final speed) Distance = ½ * (preliminary speed + very final speed) * time Distance = 8.a million m, preliminary speed = 0 m/s, very final speed = a million.8 m/s 8.a million = ½ * (0 + a million.8) * t Time = 8.a million ÷ 0.9 = 9 seconds Acceleration = (very final speed – preliminary speed) ÷ time Acceleration = (a million.8 – 0) ÷ 9 = 0.2 m/s^2 23 – µ * 137.2 = 14 * 0.2 resolve for µ</span>
6 0
3 years ago
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A helium-filled balloon is launched when the temperature at ground level is 27.8°c and the barometer reads 752 mmhg. if the ball
ololo11 [35]
The helium may be treated as an ideal gas, so that
(p*V)/T =constant
where
p = pressure
V = volume
T = temperature.

Note that
7.5006 x 10⁻³ mm Hg = 1 Pa
1 L = 10⁻³ m³

Given:
At ground level,
p₁ = 752 mm Hg
     = (752 mm Hg)/(7.5006 x 10⁻³ mm Hg/Pa)
     = 1.0026 x 10⁵ Pa
V₁ = 9.47 x 10⁴ L = (9.47 x 10⁴ L)*(10⁻³ m³/L)
     = 94.7 m³
T₁ = 27.8 °C = 27.8 + 273 K
     = 300.8 K

At 36 km height,
P₂ = 73 mm Hg = 73/7.5006 x 10⁻³ Pa
     = 9.7326 x 10³ Pa
T₂ = 235 K

If the volume at  36 km height is V₂, then
V₂ = (T₂/p₂)*(p₁/T₁)*V₁
     = (235/9.7326 x 10³)*(1.0026 x 10⁵/300.8)*94.7
     = 762.15 m³

Answer: 762.2 m³  
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3 years ago
What is the magnification of a real image if the image is 15.0 cm from a lens and the object is 60.0 cm from the lens?
Hoochie [10]

Answer:

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Explanation:

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2 years ago
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IgorC [24]

Answer:

B. Both electric fields and forces ...

Explanation:

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