Answer:
2.19 N/m
Explanation:
A damped harmonic oscillator is formed by a mass in the spring, and it does a harmonic simple movement. The period of it is the time that it does one cycle, and it can be calculated by:
T = 2π√(m/K)
Where T is the period, m is the mass (in kg), and K is the damping constant. So:
2.4 = 2π√(0.320/K)
√(0.320/K) = 2.4/2π
√(0.320/K) = 0.38197
(√(0.320/K))² = (0.38197)²
0.320/K = 0.1459
K = 2.19 N/m
Answer: 655.7 nm
Explanation:
Given
The slits are separated by 
Distance between slits and screen is 
Adjacent bright fringes are 
apart
Also, the distance between bright fringes is given by
![\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cbeta%20%3D%5Cdfrac%7B%5Clambda%20D%7D%7Bd%7D%5Cquad%20%5B%5Clambda%3D%5Ctext%7BWavelength%20of%20light%7D%5D%5C%5C%5C%5C%5Ctext%7BInsert%20the%20values%7D%5C%5C%5C%5C%5CRightarrow%202.88%5Ctimes%2010%5E%7B-3%7D%3D%5Cdfrac%7B%5Clambda%20%5Ccdot%202.24%7D%7B0.510%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5C%5CRightarrow%20%5Clambda%20%3D%5Cdfrac%7B2.88%5Ctimes%2010%5E%7B-3%7D%5Ctimes%200.510%5Ctimes%2010%5E%7B-3%7D%7D%7B2.24%7D%5C%5C%5C%5C%5CRightarrow%20%5Clambda%20%3D0.6557%5Ctimes%2010%5E%7B-6%7D%5C%20m%5C%5C%5CRightarrow%20%5Clambda%20%3D655.7%5C%20nm)
The center of the sun gets up to at least 27 million degrees Fahrenheit.
