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Greeley [361]
3 years ago
12

A bus accelerates at -0.5 m/s2 for 12.5 seconds . If the bus had an initial speed of 31 m/s, what is its new speed? A. 12.25m/s

B. 37.25m/s C. 24.75m/s D. 6.25m/s
Physics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

37.5m/s

Explanation:

a=(v-u)/t

0.5 = (v - 31) / 12.5

v - 31 = 0.5 x 12.5

v - 31 = 6.25

V = 6.25 + 31

v = 37.25m/s

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g=\frac{GM}{r^2}\\\Rightarrow g=\frac{6.67\times 10^{-11}\times 4.8\times 10^{22}}{\left(\frac{3138000}{2}\right)^2}\\\Rightarrow g=1.3\ m/s^2

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