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Arlecino [84]
3 years ago
10

Sarah invested 12000 in a unit trust 5 years ago, the value of the unit trust has increased by 7% per annum for the last 3 years

. before this the price had decreased by 3% per annumCalculate the current price of the unit trust
Physics
2 answers:
miss Akunina [59]3 years ago
8 0

Answer:

The value of the fund today is $13831.72

Explanation:

Let us calculate the value at the end of each year, step by step. An annual  decrease of 3% corresponds to a multiplier 1.0-0.03 = 0.97. An increase of 7% corresponds to 1.07.

Value at the end of

year 1: 12000 * 0.97

year 2: 12000 * 0.97 * 0.97

year 3: 12000 * 0.97 * 0.97 * 1.07

year 4: 12000 * 0.97 * 0.97 * 1.07 * 1.07  

year 5: 12000 * 0.97 * 0.97 * 1.07 * 1.07 * 1.07 = 13831.72

The value of the fund today (end of year 5) is $13831.72

Damm [24]3 years ago
3 0

The Answer to this question is

Value fund is $13831.72

Hope this helps (;

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skelet666 [1.2K]

In this question all required information's are already provided. Based on these details the answer to the question can be easily determined. Let us now write down all the information's that are already given.

Mass of the roller coaster = 1000 kg

Velocity of the roller coaster = 20.0 m/s

We know the formula for finding the kinetic energy is

Kinetic energy = 0.5 * mass * (velocity) ^2

                      = 0.5 * 1000 * (20)^2

                      = 0.5 * 1000 * 400

                      = 200000 Joules

So the Kinetic energy of the roller coaster is 200000 joules.

i hope this helps you friend good luck on your quiz or lesson

6 0
2 years ago
Identify the type of wave in the picture please asap
pychu [463]

Answer:

It is transverse wave

Explanation:

7 0
3 years ago
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Calculat the acceleration of a person at latitude<br> 40degreesowing to the rotation of the earth.
beks73 [17]

Answer:

acceleration of person = 9.77 m/s²

Explanation:

given data

latitude = 40 degree

to find out

Calculate the acceleration of a person

solution

we know that here 40 degree = 0.698 rad

so

acceleration of person = g - ω²R    ...............1

and 1 rotation complete in 24 hours = 360 degree

here g is 9.81

so we know Earth angular speed ω = 7.27 × 10^{-5} rad/s and R is earth radius that is 6.37 × 10^{6} m

so

put here value in equation 1 we get

acceleration of person = g - ω²R

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acceleration of person = 9.77 m/s²

6 0
4 years ago
In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg,
Studentka2010 [4]

Answer:

Second Trial satisfy principle of conservation of momentum

Explanation:

Given mass of ball A and ball B =\ 1.0\ Kg.

Let mass of ball A and B\ is\ m  

Final velocity of ball A\ is\ v_1

Final velocity of ball B\ is\ v_2

initial velocity of ball A\ is\ u_1

Initial velocity of ball B\ is\ u_2

Momentum after collision =mv_1+mv_2

Momentum before collision = mu_1+mu_2

Conservation of momentum in a closed system states that, moment before collision should be equal to moment after collision.

Now, mu_1+mu_2=mv_1+mv_2

Plugging each trial in this equation we get,

First Trial

mu_1+mu_2=mv_1+mv_2\\1(1)+1(-2)=1(-2)+1(-1)\\1-2=-2-1\\-1=-3

momentum before collision \neq moment after collision

Second Trial

mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1.5)=1(-.5)+1(-.5)\\.5-1.5=-.5-.5\\-1=-1

moment before collision = moment after collision

Third Trial

mu_1+mu_2=mv_1+mv_2\\1(2)+1(1)=1(1)+1(-2)\\2+1=1-2\\3=-1

momentum before collision \neq moment after collision

Fourth Trial

mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1)=1(1.5)+1(-1.5)\\.5-1=1.5-1.5\\-.5=0

momentum before collision \neq moment after collision

We can see only Trial- 2 shows the conservation of momentum in a closed system.

4 0
3 years ago
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vladimir2022 [97]

Answer:

The faster an object moves, the more kinetic energy it has. The more mass an object has, the more kinetic energy it has.

Explanation:

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