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NeX [460]
2 years ago
14

Would a 2021 Ford Mustang GT be light weight or heavy weight?​

Physics
1 answer:
xxTIMURxx [149]2 years ago
5 0

Answer:

Heavy weight

Explanation:

It's a muscle car, its weight its 3,825 lb, and it's classified as heavy for a car.

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A pencil has a density of 0.875 g/ml. It has a volume of 4.0 ml. Find the mass
loris [4]

Answer:

To find the mass using density and volume we just multiply them against each other which causes ml to cancel and just leaves us with grams which represents how much the item weights.

mass=density*volume

mass=0.875\frac{g}{ml}*4.0\ ml

mass=3.5\ g

Therefore, our final answer is that our pencil weight 3.5 grams

<u><em>Hope this helps!  Let me know if you have any questions</em></u>

3 0
2 years ago
1. Where is the water in the pot going?
Citrus2011 [14]

Answer:

   

Explanation:

   

3 0
2 years ago
Relative formula mass of CuCO3
Elodia [21]

AnMolar mass of CuCO3 = 123.5549 g/mol

This compound is also known as Copper(II) Carbonate.

Convert grams CuCO3 to moles  or  moles CuCO3 to grams

Molecular weight calculation:

63.546 + 12.0107 + 15.9994*3

Percent composition by element

Element   Symbol   Atomic Mass   # of Atoms   Mass Percent

Copper Cu 63.546 1 51.431%

Carbon C 12.0107 1 9.721%

Oxygen O 15.9994 3 38.848%

Explanation:

5 0
2 years ago
Hey! I found this question quite interesting. Check it out - https://www.meritnation.com/ask-answer/question/to-raise-a-200kg-st
Yanka [14]

Answer:

yes yes so do I

6 0
3 years ago
William Tell shoots an apple from his son's head. The speed of the 102-g arrow just before it strikes the apple is 26.7 m/s, and
xxMikexx [17]

To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.

By definition the conservation of momentum tells us that,m_1V_1+m_2V_2 = (m1+m2)V_f

To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,

t= \sqrt{\frac{2h}{g}}

The linear velocity of an object is given by

V=\frac{X}{t}

Replacing the equation of time we have to,

V_f = \frac{X}{t}\\V_f =\frac{X}{\sqrt{\frac{2h}{g}}}\\V_f = \frac{6.9}{\sqrt{\frac{2(1.85)}{9.8}}}\\V_f = 11.23m/s

Velocity two is neglected since there is no velocity of said target before the collision, thus,

m_1V_1 = (m1+m2)V_f

Clearing for m_2

m_2 = \frac{m_1V_1}{V_f}-m_1\\m_2 = \frac{(0.102)(26.7)}{11.23}-0.102\\m_2 = 0.1405KG= 140.5g

8 0
3 years ago
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