All categories

2 years ago

Would a 2021 Ford Mustang GT be light weight or heavy weight?

Physics

1 answer:

xxTIMURxx [149]2 years ago

5 0

Answer:

Heavy weight

Explanation:

It's a muscle car, its weight its 3,825 lb, and it's classified as heavy for a car.

You might be interested in

What si unit measures speed ?

dlinn [17]

Hmm doesnt soujd familiar

4 0

3 years ago

the police department determined that the force required to drag a 130 N(29 lb) car tire across the pavement at a constant veloc

ki77a [65]

The force of friction is given by:
f = μR, where μ is the friction coefficient and R is the reaction force, which will be equal to the weight.
100 = μ x 130
μ = 0.77

4 0

3 years ago

Mumz [18]

No se ha da han dicho nada más de lo dicho y han ido de vuelta y han dicho nada más de que se pueda hacer el favor del niño

4 0

3 years ago

Read 2 more answers

A golfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. She launch

Lina20 [59]

Answer:

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

$x=V_{o}cos \theta t$ ----------------------(1)

$y=y_{o}+V_{o} sin \theta t - \frac{1}{2}gt^{2}$ ---------(2)

$V=V_{o}-gt$ ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

$V_{o}$ is the golf ball's initial velocity

$\theta=0\°$ is the angle (it was a horizontal shot)

t is the time

y is the final height of the ball

$y_{o}$ is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

$t=\sqrt{\frac{2 y_{o}}{g}}$

$t=\sqrt{\frac{2 (12.5 m)}{9.8 m/s^{2}}}$

$t=1.597$ s

Substituting (6) in (1):

$67.1 =V_{o} cos(0\°) 1.597$ -------------------(4)

Step 2: Finding $V_{o}$ :

From equation(4)

$67.1 =V_{o}(1) 1.597$

$V_0 = \frac{6.71}{1.597}$

$V_{o}=42.01$ m/s (8)

Substituting $V_{o}$ in (3):

$V=42.01 -(9.8)(1.597)$

v =42 .01 - 15.3566

V=26.359 m/s

5 0

3 years ago

Define the difference between the rigid body problem and a single particle problem.

agasfer [191]

. In single particle problem whole mass is concentrated at a single point so it has a single displacement, single velocity and single acceleration. while, in rigid body mass is distributed

3 0

3 years ago

Would a 2021 Ford Mustang GT be light weight or heavy weight?​

Would a 2021 Ford Mustang GT be light weight or heavy weight?