Hey there!
C₉H₂O + O₂ → CO₂ + H₂O
First let's balance the C.
There's 9 on the left and 1 on the right. So, let's add a coefficient of 9 in front of CO₂.
C₉H₂O + O₂ → 9CO₂ + H₂O
Next let's balance the H.
There's 2 on the left and 2 on the right. This means it's already balanced.
C₉H₂O + O₂ → 9CO₂ + H₂O
Lastly, let's balance the O.
There's 3 on the left and 19 on the right. So, let's add a coefficient of 9 in front of O₂.
C₉H₂O + 9O₂ → 9CO₂ + H₂O
This is our final balanced equation.
Hope this helps!
Answer:
I believe the answer is B.) Reflection
I hope I helped! ^-^
8 grams
A <span>2.0%m/v</span> (mass/volume) solution is 2 grams of solute in 100 mL of final solution.
So for 400 mL of solution, you require
<span>400mL⋅<span>2 g<span>100mL</span></span>=<span>8 g</span></span>
