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pishuonlain [190]
3 years ago
10

PLS HELP I WILL MARK BRAINLIEST NO LINKS OR PDFS AND PLSEXPLAIN YOUR ANSWER CLEARLY THANKYOU

Chemistry
2 answers:
Butoxors [25]3 years ago
8 0

Answer:If each side of the equation has the same number of atoms of a given element, that element is balanced. If all elements are balanced, the equation is balanced. - online resource

Explanation: if not im sorry

galina1969 [7]3 years ago
6 0
There are the same amount of each type of atoms on the left side as there are on the right side.
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What is the concentration of k+ ions in a 0.045 m k2co3 solution assuming complete dissociation?express the concentration in mol
kykrilka [37]
<span>(0.045) x (2 K{+} ions / 1 molecule K2CO3) = 0.090 in whatever units the original concentration was expressed in</span>
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3 years ago
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Ammonia (NH3) ionizes according to the following reaction: NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH–(aq) The base dissociation constant
Ira Lisetskai [31]

Answer:

pH = 9.6

Explanation:

According to Brönsted-Lowry theory, NH₃ is a base and NH₄⁺ its conjugate acid. When they are together in a solution, the form a buffer, which is used to resist abrupt changes in pH when an acid or a base is added. pOH fro a buffer can be found using Henderson-Hasselbalch equation.

pOH = pKb + log\frac{conjugateacid}{base}

Since NH₄Cl is a strong electrolyte, [NH₄Cl] = [NH₄⁺]

pOH = pKb + log\frac{[NH_{4}^{+} ]}{[NH_{3}]} =4.7+log\frac{0.035M}{0.070M} =4.4

Now, we can find pH using the following expression:

pH + pOH = 14

pH = 14 - pOH = 14 - 4.4 = 9.6

7 0
4 years ago
18.53 For CaO, the ionic radii for Ca2 and O2 ions are 0.100 and 0.140 nm, respectively. If an externally applied electric field
gogolik [260]

Answer:

= 1.92*10^-^3^0 C.m

Explanation:

Given:

r_ca_^2_^+ = 0.100 nm

r_o_^2_^- = 0.14 nm

Let's find the distance of separation between cation and anion when there is no applied electric field with the formula:

d = r_ca_^2_^+ + r_o_^2_^-

d = 0.100 nm + 0.140 nm

= 0.240 nm

Let's also calculate the distance of separation between anion and cation when there is an applied electric field.

We use the formula:

∆d = 5%d => 0.05d

= 0.05 * 0.024 nm

∆d = 0.0120 nm

0.120* 10^-^9m

= 1.20*10^-^1^1m

Given magnitude of each dipole= 1.602*10^-^1^9 C

Let's find the dipole moment, with the formula:

p = q∆d

Substituting figures in the formula, we have:

p = 1.602*10^-^1^9 * 12*10^-^2^1

= 1.92*10^-^3^0 C.m

5 0
3 years ago
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You have a cup of water and a packet of powdered juice mix. You add some of the juice mix to the cup of water and stir. The powd
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The correct answer is "The solution is immiscible".

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However, a misicible solution is one where two or more substances mix in each other to form a homogeneous solution.

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Find out more on Hydraulic fracturing at: brainly.com/question/1990340

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2 years ago
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