A patient being treated for thyroid cancer is to receive a dose of iodine-131. The typical dose is 4.5 uCi/kg of body weight.

Chemistry

1 answer:

Ilia_Sergeevich [38]4 years ago

4 0

Answer:

You would need 328.5 uCi.

Explanation:

Since you need 4.5 uCi per kilogram of body weight then you would multiply 4.5 with their body weight in kilograms to get the answer.

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The tendency of an atom to pull electrons toward itself is referred to as its _____. ionic potential tonicity covalency electron

larisa86 [58]

Electronegativity

The tendency of an atom to pull electrons towards itself is called electronegativity.

It is the tendency of an atom to attract bonding pair of electrons towards itself. These atoms which are more electronegative are able to bear a negative charge and be stable.

Unlike electropositive elements which tend to lose electrons , electronegative elements hold on tightly to the electrons.

The electronegativity is measured using the Pauling Scale where the most electronegative element of the periodic table, Fluorine , is given a value of 4 and the rest of the elements have values lower than 4 according to the trends followed by their groups and periods.

The least electronegative element of the periodic table , Cesium has a value of 0.7 on the Pauling Scale.

Electronegativity increases when we move from left to right in the periodic table and it decreases (in general) when we move down the group.

(To know more about Electronegativity: https://brainly.in/question/5742635 )

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1 year ago

Which is the strongest acid? Ch3ch2ch2chfch2co2h ch3ch2ch2cbr2ch2co2h ch3ch2ch2cf2ch2co2h ch3chbrch2ch2ch2co2h ch2clch2ch2ch2ch2

liq [111]

The strength of an acid increases if the stability of conjugate base increases

The stability of a conjugate base increases with the presence of electron with drawing group (electronegative group)

Thus more the electronegativity of an atom attached to a carboxylic acid higher the strength of acid

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8 0

3 years ago

A chemist studies the reaction below. 2NO(g) + Cl2(g) 2NOCl(g) He performs three experiments using different concentrations and

Dmitry_Shevchenko [17]

Answer:

1. $Rate =k [NO]^{2}[Cl_{2}]$

2. $k= 0.42 \frac{L^{2}}{mol^{2}*s}$

Explanation:

$Rate =k [NO]^{m}[Cl_{2}]^{n}$

$Rate1 = k[0.4]^{m}[0.3]^{n}=0.02\\Rate 2=k [0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate1}{Rate2}=\frac{0.02}{0.08} =\frac{k[0.4]^{m}[0.3]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{1}{4} =(\frac{1}{2} )^{m},\\m=2$

$Rate3 =k [0.8]^{m}[0.6]^{n}=0.16\\Rate 2= k[0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate3}{Rate2}=\frac{0.16}{0.08} =\frac{k[0.8]^{m}[0.6]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{2}{1} =(\frac{2}{1} )^{n},\\n=1$

$Rate =k [NO]^{2}[Cl_{2}]^{1}$

$Rate =k [NO]^{2}[Cl_{2}]^{1}\\Rate 1=k [0.4]^{2}[0.3]^{1} =0.02\\k*0.16*0.3=0.02\\k=\frac{0.02}{0.16*0.3}=\frac{1}{8*(\frac{3}{10} )}=\frac{5}{12} = 0.42 \frac{L^{2}}{mol^{2}*s}$