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Romashka [77]
3 years ago
8

A patient being treated for thyroid cancer is to receive a dose of iodine-131. The typical dose is 4.5 uCi/kg of body weight.

Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

You would need 328.5 uCi.

Explanation:

Since you need 4.5 uCi per kilogram of body weight then you would multiply 4.5 with their body weight in kilograms to get the answer.

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1.2 moles of (NH4)3PO3
Aleks04 [339]
1.2 moles of (nph4)3po3 is.......159.6 grams
3 0
3 years ago
Relate the strength of a weak acid to the strength of a conjugate base.
Elenna [48]

Answer:

There is a relationship between the strength of an acid (or base) and the strength of its conjugate base (or conjugate acid): The stronger the acid, the weaker its conjugate base.  The weaker the acid, the stronger its conjugate base.  The stronger the base, the weaker its conjugate acid.

explanation

The strength of an acid and a base is determined by how completely they dissociate in water. Strong acids (like stomach acid) break down or dissociate in water. Weak acids maintains their protons in water.

4 0
3 years ago
Fe(s) + 2HCl(aq) --> FeCl2(aq) + H2(g)
soldier1979 [14.2K]

Answer:

In the option(A) moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

Explanation:

Fe(s) + 2HCl(aq)\rightarrow  FeCl_2(aq) + H_2(g)


Moles of HCl = n

Molarity of HCl = 1.0M

Volume of HCl solution = 30.0 mL = 0.030 L (1 mL = 0.001L)

Moles=Molarity\times Volume (L)

n=1.0M\times 0.030 L=0.030 mol

Moles of Fe = \frac{0.56 g}{56 g/mol}=0.01 mol

According to recation , 1mol of Fe reacts with 2 mol HCl. Then 0.01 mole of Fe will recat with :

\frac{2}{1}\times 0.01 mol= 0.02 mol of HCl

This means that HCl uis in excess , hence excessive reagent.

Moles of HCl left unreacted :

= 0.030 mol - 0.020 mol = 0.010 mol

But in the option moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

8 0
3 years ago
PLS HELPPPP NOWWWW!!!!
dedylja [7]
When in doubt pick C I don’t really know the answer but I just pick C
8 0
2 years ago
How many atoms are in 1.75 mol CHCL3
vaieri [72.5K]

1 mol = 6.022 x 10²³ atoms

In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.

So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃

But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃

6 0
3 years ago
Read 2 more answers
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