Answer
Noble Gases
Explanation: It is noble gases On the Website Ptable it will show you all the facts you need to know about each element
2SO₂+O₂⇒2SO₃ ΔH=-197 kJ
<h3>Further explanation</h3>
Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways
Reaction
2SO₂+O₂⇒2SO₃
Given :
1. S(s)+O₂(g)→SO₂(g) ΔH = -297 kJ
Reverse
SO₂(g) ⇒S(s)+O₂(g ΔH = +297 kJ
(sign change to +) x 2
2SO₂(g) ⇒2S(s)+2O₂(g ΔH = +594 kJ
2.2S(s)+3O2(g)→2SO3(g) ΔH=-791kJ
Add both reactions and remove/subtract the same compound for different sides
1. 2SO₂(g) ⇒2S(s)+2O₂(g) ΔH = +594 kJ
2.2S(s)+3O₂(g)→2SO₃(g) ΔH=-791kJ
--------------------------------------------------------+
2SO₂+O₂⇒2SO₃ ΔH=-197 kJ
Answer:
2Mg + O2 = 2MgO
Explanation:
Al + 3F2 = AlF3 ..... F has 6 on the left and 3 on the right.
Na + F2 = 2NaF ..... Na has 1 on the left and 2 on the right.
2Al + 3O2 = Al2O3 .... O has 6 on the left and 3 on right.
Answer:
a) ΔU = 370 KJ
b) Endothermic
Explanation:
a)
The change in energy of the mixture can be given by first law of thermodynamics as:
ΔQ = ΔU + W
ΔU = ΔQ - W
where,
ΔQ = change in heat energy of system
ΔU = Change in internal energy of gases
W = Work done on gases = - 155 KJ
For an isobaric process (i.e constant pressure) we know that:
ΔQ = change in enthalpy = ΔH
ΔQ = 215 KJ
Therefore, using values in the equation, we get:
ΔU = 215 KJ - (-155 KJ)
<u>ΔU = 370 KJ</u>
b)
Since, the enthalpy of products is greater than the reactants. Therefore, this is an <u>endothermic reaction</u>.
Answer:
Subtract all the variables and do the opposite operation when added.
Explanation:
