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natali 33 [55]
3 years ago
13

When you eat a candy bar, your body oxidizes glucose to get energy. where does this energy come from? kinetic energy of the gluc

ose molecules chemical bonds within the glucose molecules work done on both oxygen and glucose molecules kinetic energy of the oxygen molecules?
Physics
1 answer:
babymother [125]3 years ago
8 0
The correct answer is
<span>"chemical bonds within the glucose molecules "

The chemical bonds of the glucose molecules contain chemical energy, and when these bonds are broken by the processes acting inside the body, the energy of the bonds is released and it can be used by the body.


</span>
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State pascal law and write three instrument which base unit?​
OLEGan [10]

Answer:

Pascal's law (also Pascal's principle[1][2][3] or the principle of transmission of fluid-pressure) is a principle in fluid mechanics given by Blaise Pascal that states that a pressure change at any point in a confined incompressible fluid is transmitted throughout the fluid such that the same change occurs everywhere.[4] The law was established by French mathematician Blaise Pascal in 1653 and published in 1663.[5][6]

7 0
2 years ago
This is the last question
koban [17]

Answer:

It's C

Explanation:

3 0
3 years ago
Read this excerpt from Through the Looking-Glass by Lewis Carroll.
Vanyuwa [196]

Answer:

Why does Alice forget the name of the woods and her own name?

6 0
3 years ago
Two points charges are brought closer together,increasing the force between them by a factor of 25.By what factor wa their separ
Roman55 [17]

Answer:

The separation between the charges was decreased by a factor of 0.2

Explanation:

The Coulomb's force between two charges is given by;

F = \frac{kq^2}{r^2} \\\\let \ kq^2 \ be \ constant\\\\F_1r_1^2 = F_2r_2^2\\\\r_2^2 = \frac{F_1r_1^2}{F_2} \\\\increasing \ the \ force \ between \ them \ by \ factor \ of \ 25\\\\(F_2 = 25F_1)\\\\r_2^2 = \frac{F_1r_1^2}{25F_1}\\\\r_2^2 = \frac{r_1^2}{25}\\\\r_2 = \sqrt{\frac{r_1^2}{25} }\\\\ r_2 = \frac{r_1}{5}

r₂ = 0.2r₁

Therefore, the separation between the charges was decreased by a factor of 0.2.

6 0
3 years ago
consider a sample of gas in a container on a comfortable spring day. the Celsius temperature suddenly doubles, and you transfer
Tasya [4]

Answer:

6.6 atm

Explanation:

Using the general gas law

P₁V₁/T₁ = P₂V₂/T₂

Let P₂ be the new pressure

So, P₂ = P₁V₁T₂/V₂T₁

Since V₂ = 2V₁ , P₁ = 12 atm and T₁ = 273 + t where t = temperature in Celsius

T₂ = 273 + 2t (since its Celsius temperature doubles).

Substituting these values into the equation for P₂, we have

P₂ = P₁V₁(273 + 2t)/2V₁(273 + t)

P₂ = 12(273 + 2t)/[2(273 + t)]

P₂ = 6(273 + 2t)/(273 + t)]

assume t = 30 °C on a comfortable spring day

P₂ = 6(273 + 2(30))/(273 + 30)]

P₂ = 6(273 + 60))/(273 + 30)]

P₂ = 6(333))/(303)]

P₂ = 6.6 atm

7 0
3 years ago
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