Answer:
The electrical force between two balloons is 67.5N.
Explanation:
There are two charged balloons, let's say a and b.
The charge on the balloon a = C
The charge on the balloon b = C
Both balloons are 1 cm apart; it means that the distance<em> r</em> between the balloon a and the balloon b is 0.01 m (since 1 cm = 0.01 m).
We need to find the electrical force between them. By using the Coulomb's law, the magnitude of the electrical force between both the balloon is given as follows:
--- (A)
Where,
k = Coulomb's constant = =
Plug all the values in the equation (A):
Hence, the electrical force between two balloons is 67.5N (three significant figures).
Here is are by step :) hope this helps
First things first, you want the resultant to be in the direction of the bearing of 105 °. The distance required is irrelevant for question 1.
You want the addition of the wind speed and the planes velocity to equal some resultant in the direction one 105 °. Draw a parallelogram (vector addition) of the resultant (the 100km in direction 105°) and the wind speed. The diagonal that results from the vector addition will equal 240. You only know the angle between the resultant and the wind speed right now (105°).
https://www.geogebra.org/geometry/rbejhvta
What is the angle between the resultant (the direction we want to travel) and the direction the plane will actually go when wind speed is taken into accound???
Law of sines.
You said you have it, so we will continue under the assumption you got 4.617°.
now, take into account that the plane is accelerating 4.617° off of the 105° bearing in order to travel on the 105° bearing when wind speed is taken into account... what heading is the plane taking? 105° - 4.617° = 100.4°
There is part 1.
now you simply need to find the actual speed she is travelling along the bearing 105°. (she is traveling 240km/h with a 100.4° heading, find the correct speed for the resultant).
EDIT: The representation says 105.1°, it is supposed to say 105°
I think the answer is proton
The wavelength of the light is 590nm
wavelength of the light=λ
Given,
The equation for a diffraction grating to use here is dsinθ = mλ
d=1/610 lines per mm=1.639*, m=1, θ=21.
λ=1.639* * sin21./1 =590nm
<h3>Wavelength </h3>
The wavelength, which in physics refers to the length over which a periodic wave repeats, is its spatial period. It is the distance between two successive corresponding wave points of the same phase, such as two neighbouring crests, troughs, or zero crossings, and it is a feature of both travelling waves and standing waves, as well as other spatial wave patterns. The spatial frequency is defined as the wavelength's inverse. The Greek letter lambda, or "wavelength," is frequently used to represent it. Additionally, sinusoidal wave envelopes, modulated waves, and waves created by the interference of several sinusoids are also commonly referred to as having a wavelength.
You measure an angle of 21. 1 when the light passes through a grating with 610 lines per mm. what is the wavelength of the light?
Learn more about wavelength here:
brainly.com/question/13533093
#SPJ4
-- She went up for 0.4 sec and down for 0.4 sec.
-- The vertical distance traveled in gravity during ' t ' seconds is
D = (1/2) x (g) x (t)²
= (1/2) (9.8 m/s²) (0.4 sec)²
= (4.9 m/s²) x (0.16 s²)
= 0.784 meter ( B )