Answer:
Work done.
Explanation:
The skater who lifts has to overcome the partner's weight. When lifted up by 1 meter, her potential energy increases by (mass)x(gravitational acceleration)x(1meter), which is the amount of work done.
(This all assumes lifting vertically and no other forces being part of the picture)
To be considered a source of water pollution, the source must include a chemical is false.
<u>Explanation:
</u>
The water pollution may be caused either by chemicals or waste materials that doesn’t contain chemicals such as domestic wastes, organic compounds, heavy metals etc. The life on Earth mostly relies on water and air, and if these two gets polluted; the results will be dangerous.
Around 70% of the planet is covered with water and the present state of its purity is a matter of a serious thought. Looking over various pollutants, only chemical wastes are not responsible to pollute the water.
Instead, there is range of elements from plastic scraps to chemical wastes that comes from either the non-point sources or the point sources. There are organic waste materials, heavy metals, volcanic eruptions, Tsunamis, earthquakes, etc. are also responsible to contaminate water and affect the amphibians as well as humans.
Answer:
A.) 39.5 m
B.) 0
C.) 60m/s^2
Explanation:
Given that a displacement function of a particle is x(t)=(20t^2-15t+200).
To Find the total displacement,
Reduce everything by dividing them by 5
X(t) = 4t^2 - 3t + 40 ...... (1)
For instantaneous velocity, differentiate x(t). That is,
dy/dt = 60t - 15 ...... (2)
But dy/dt = velocity.
If dy/dt = 0, then
60t - 15 = 0
60t = 15
t = 15/60
t = 0.25s
Substitutes t in equation (1)
Total displacement will be
X(t) = 4(0.25)^2 - 3(0.25) + 40
X(t) = 0.25 - 0.75 + 40
Total displacement = 39.5 m
To calculate instantaneous velocity, substitute t into equation (2)
V = 60 (0.25) - 15
V = 0.
and to find instantaneous acceleration, differentiate dv/dt
dv/dt = 60
Therefore, acceleration = 60 m/s^2
Complete Question
A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.
Answer:
The value 
Explanation:
From the question we are told that
The charge on the first sphere is 
The charge on the second sphere is 
The mass of the second charge is 
The distance apart is 
The speed of the second sphere is 
Generally the total energy possessed by when 
and 
are separated by 
is mathematically represented
Here KE is the kinetic energy which is mathematically represented as
substituting value
And U is the potential energy which is mathematically represented as
substituting values
So
Generally the total energy possessed by when and are separated by 
is mathematically represented
Here 
is the kinetic energy which is mathematically represented as
substituting value
And 
is the potential energy which is mathematically represented as
substituting values
From the law of energy conservation
So
The phenomena<span> of </span>atmospheric<span> electricity are of three kinds. ..... In the Earth-</span>ionosphere cavity, the electric field<span> and conduction current in the lower </span>atmosphere<span> </span>
