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Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :



F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
The magnitude of your displacement can be equal to the distance you covered, or it can be less than the distance you covered. But it can never be greater than the distance you covered.
This is because displacement is a straight line, whereas distance can be a straight line, a squiggly line, a zig-zag line, a line with loops in it, a line with a bunch of back-and-forths in it, or any other kind of line.
The straight line is always the shortest path between two points.
0.74in
Explanation:
Given parameters:
length range of adult mosquito = 3.0 - 6.0mm
Smallest mosquito = 2.5mm
Largest mosquito = 19mm
Average mass range = 3.0 - 5.0mg
Unknown:
Length of largest known mosquito in inches = ?
Solution;
The length is the longest dimension. It is how long a body is.
The problem here is converting from mm to inches;
The length of the longest mosquito which is the largest is 19mm
19mm to inches;
1mm = 0.039inches
19mm = 19mm x
= 0.74in
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