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Mazyrski [523]
3 years ago
9

Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble

A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of −0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.
Physics
1 answer:
Neporo4naja [7]3 years ago
4 0

Answer:

2.4 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.08 kg)(0.5 m/s) + (0.05 kg)(0 m/s) = (0.08 kg)(-0.1 m/s) + (0.05 kg) v

0.04 kg m/s = -0.08 kg m/s + (0.05 kg) v

0.12 kg m/s = (0.05 kg) v

v = 2.4 m/s

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The label has been scratched off a tuning fork and you need to know its frequency. From its size, you suspect that it is somewhe
Natali5045456 [20]

Answer:

255 Hz

Explanation:

The beat frequency is the difference in frequency between two frequencies that are close.

Let the the unknown frequency be f.

Sounded with the 250 Hz tuning fork,

|250-f|=5

f = 255 \text{ or } 245

Sounded with the 270 Hz tuning fork,

|270-f|=15

f = 255 \text{ or } 285

The common value of f in both situations is 255 Hz.

3 0
3 years ago
A spring has a natural length of 0.5 m and was stretched by 0.02 m. if the spring had a resultant energy of 0.5 j what is the sp
Anna71 [15]

\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}

Explanation:

       Natural length of a spring is 0.5\text{ }m. The spring is streched by 0.02\text{ }m. The resultant energy of the spring is 0.5\text{ }J.

       The potential energy of an ideal spring with spring constant k and elongation x is given by \dfrac{1}{2}kx^{2}.

       So, in the current problem, the natural length of the spring is not required to find the spring constant k.

       \text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}

∴ The spring constant of the spring = 2500\text{ }\frac{kg}{s^{2}}

4 0
4 years ago
Beats are the difference in (a) Frequency (b) Amplitude (c) Intensity (d) None
sasho [114]

Answer:

Beats are the difference in frequency.

(a) is correct option.

Explanation:

Beat :

Beat is the difference of the frequency of two waves.

The difference in frequency is equal to the number of beat per second.

Amplitude :

Amplitude of the wave is the maximum displacement.

Frequency :

Frequency is the number oscillations of wave in per second.

Intensity :

Intensity is the power per unit area.

Hence, Beats are the difference in frequency.

7 0
3 years ago
A toy truck has a speed of 3 m/s and kinetic of 36 J what is its mass?
Scorpion4ik [409]

Answer:

12

Explanation:

The equation is w= f *d

36=3*d

12=d 12 units is the mass

6 0
3 years ago
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velikii [3]

Answer:

A. negatively charged are deposited on the belt, which deposits positive charges on the metal ball.

Explanation:

Negatively charged ions are injected at one end of thebelt towards the high potntial terminal, where they are acclerated by attractive forces towards the terminal. When the particles reach the terminal, they are stripped of some electrons to make them positively charged.

5 0
3 years ago
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