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sukhopar [10]
3 years ago
11

Shear stress created the San Andreas Fault in Southern California. It is an example of a _____.

Physics
2 answers:
cupoosta [38]3 years ago
7 0
Shear stress created the San Andreas Fault in Southern California. It is an example of a <span>reverse fault.</span>
OlgaM077 [116]3 years ago
4 0

strike-slip fault is the answer

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It's cold outside, the water vaper in your breath condenses into tiny droplets of liquid water and ice that you can see.
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Sound travels slowest through gas because the atoms in a gas are further apart than the other states of matter.
Tanzania [10]

Answer:

false

Explanation:

If they were farther apart they would be able to slip by through which means that it can go by faster. If the atoms where closer together then yes they would be able to go by slower.

8 0
2 years ago
Lagrangian mechanics. Determine the equations of motion for a particle of mass m constrained to move on the surface of a cone in
maria [59]

Answer:

Explanation:

Hi!

In order to obtain the Lagrangian of the system we must first write the Kinetic and Potential Energies. Lets orient our axes such that the axis of the cone coincide with the z axis. In cilindrical coordinates we have

v^{2} = \frac{dr}{dt}^{2}  +r^{2} \frac{d\theta }{dt} ^{2} +\frac{dz}{dt} ^{2} - (1)

But, since the particle is constrained to move on the surface of the cilinder, we have the following relation between r and z:

\frac{r}{z}=tan(45)

or:

z = r cot(45) - (2)

and:

\frac{dz}{dt} = \frac{dr}{dt} cot(45)

replacing (2) in (1) we obtain:

v^{2} = \frac{dr}{dt}^{2} (1+cot(45))+r^{2}\frac{d\theta }{dt} ^{2}  - (3)

Now the kinetic energy is given as:

T = \frac{1}{2}m(\frac{dr}{dt}^{2} (1+cot(45))+r^{2}\frac{d\theta }{dt} ^{2}) - (4)

And the potential energy is given by:

V = -mgz = -mgr cot(45)

So the Langrangian is given by:

L = T - V= \frac{1}{2}m(\frac{dr}{dt}^{2}(1+cot(45)+r^{2})\frac{d\theta }{dt} ^{2}) + mgr cot(45)

And the equations of motion are:

For θ

\frac{d}{dt} (mr\frac{d\theta}{dt}) = 0-->mr{d\theta}{dt}=c

For r

\frac{d}{dt}(m\frac{dr}{dt}(1+cot(45) )= mgcot(45)+mr\frac{d\theta}{dt} ^{2}\\m\frac{d^{2} r}{dt^{2} }(1+cot(45)= mgcot(45)+mr\frac{d\theta}{dt} ^{2}

Obtained from the Euler-Langrange equations

Here the conserved quantity is given by the first equation of motion, namely:

mr\frac{d\theta}{dt}=c

Which is the magnitude of the angular momentum

7 0
3 years ago
The distance between Pluto and the Sun is 39.1 times more than the distance between the Sun and Earth. Calculate the time taken
german

Answer:

Explanation:

Given

Distance between Pluto and sun is 39.1 times more than the distance between earth and sun

According to Kepler's Law

T^2=kR^3

where k=constant

T=time period

R=Radius of orbit

Suppose R_1 is the radius of orbit of earth and sun

so Distance between Pluto and sun is R_2=39.1\cdot R_1

T_1 and T_2 is the time period corresponding to R_1 and R_2[/tex]

(T_1)^2=k(R_1)^3---1

(T_2)^2=k(R_2)^3---2

divide 1 and 2

(\frac{365}{T_2})^2=(\frac{R_1}{39.1})^3

T_2^2=365^2\times 39.1^3

T_2=89239.67\ Earth\ days                      

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