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Archy [21]
3 years ago
11

All the formulas for Friction​

Physics
1 answer:
notka56 [123]3 years ago
6 0

Answer:

f = \mu N

Explanation:

Newton’s 2nd Law

o Fnet = mass x acceleration = m * a

o If force is gravitational (Fg or weight↓),

 Weight = mass * gravitational acceleration

 Weight = m * g

Kinematic Equations (general)

o vf = v0 + at

o vf

2

= v0

2

+ 2ad

o d = v0t + ½ at2

Inclined Plane ( ) - F|| vs Ff

o F|| down plane (causing motion) = mg sin

o Ff up plane (friction force opposing motion) = mg cos

Friction

o Coefficient = Force of friction (Ff) (0 < <1)

Normal force (FN)

Ff = FN

Net Force (Fnet)

o Flat plane: Fnet = Fa – Ff = Fa – μmg

o Inclined plane: Fnet = F|| - Ff = mgsinθ = μmgcosθ

Pressure

o P = Applied force

area of application

o P = F/A (= mg/A when using a gravity or weight model)

Conversion

o cm2

x 10-4

= m2

o mm2

x 10-6

= m2

Units

o Force - Newtons

o Pressure - N/m2

or Pascals (Pa)

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RUDIKE [14]

Answer:

a) current in the second wire is 5.60A

b) opposite directions

Explanation:

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\frac{F}{L} = \frac{U_0I^1}{2\pi r} \\\\I^1 = \frac{F2\pi r}{LU_0I}

= (3.6 * 10^-^5)\frac{2\pi (0.02)}{4\pi * 10^-^7)(0.64)} \\= 5.60A

b) knowing that for a two parallel conductor carrying current in the same direction attracts each other, and for a two parallel conductors carrying carying current in opposite direction repels eachother.

therefore, since the two wire repel each other then the current in the second wire must flow in the opposite direction of the current in the first wire.

7 0
4 years ago
A 56 kg astronaut stands on a bathroom scale inside a rotating circular space station. The radius of the space station is 250 m.
Zielflug [23.3K]

Answer:

The speed of space station floor is 49.49 m/s.

Explanation:

Given that,

Mass of astronaut = 56 kg

Radius = 250 m

We need to calculate the speed of space station floor

Using centripetal force and newton's second law

F=mg

\dfrac{mv^2}{r}=mg

\dfrac{v^2}{r}=g

v=\sqrt{rg}

Where, v = speed of space station floor

r = radius

g = acceleration due to gravity

Put the value into the formula

v=\sqrt{250\times9.8}

v=49.49\ m/s

Hence, The speed of space station floor is 49.49 m/s.

6 0
3 years ago
A jogger moves from a position x =
vlada-n [284]

Answer:

3 m/s

Explanation:

We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:

Initial displacement (d₁) = 4 m

Final displacement (d₂) = 16 m

Change in displacement (Δd) =?

Δd = d₂ – d₁

Δd = 16 – 4

Δd = 12 m

Finally, we shall determine the determine the average velocity. This can be obtained as follow:

Change in displacement (Δd) = 12 m

Time (t) = 4 s

Velocity (v) =?

v = Δd / t

v = 12 / 4

v = 3 m/s

Thus, the average velocity of the jogger is 3 m/s

5 0
3 years ago
Josh and Jake are both helping to build a brick wall which is 6 meters in height. They each lay 250 bricks, but Josh finishes th
Molodets [167]
<span>Each laid 250 bricks but while Jake was still working, Josh was lounging in the shade. Josh has more power but that power was only on for 3 hours out of 4.5. Obviously Josh could get more done is less time as long as he keeps working. Jake will get the hang of it soon.</span>
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Answer:

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Explanation:

First change the minutes into hours then multiply by the distance.

(8÷60)×120=16km

5 0
4 years ago
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