The formula for aluminum fluoride is electrically neutral which of the following is the correct

A student used 1.2 g of hydrate in the first trial and 1.6 g in the second trial. Explain fully why her mass percent of water wi

Pachacha [2.7K]

Both trials of 1.2 g and 1.6 g will have the same mass percent of water because the ratio of the salt to the water of hydration is always constant for any hydrated salt.

<h3>Water of hydration</h3>

For every hydrated salt, the ratio of the salt to the water of hydration remains constant irrespective of the amount of salt taken for experimental analysis.

For example, assuming the mass percent of water in 10g of a hydrated salt is 40%, if 100g of the same salt is taken, the mass percent will remain 40%.

More on water of hydration can be found here: brainly.com/question/11202174

8 0

2 years ago

2. Answer the following questions about a sample of calcium phosphate:

weqwewe [10]

Answer:

a) 310.18 g/mol

b) 4.352 moles Ca3(PO4)2

c) 2.6 * 10^24 molecules

d) 5.24 * 10^24 P atoms

e)13.056 moles Ca

f)10825.3 grams

Explanation:

Step 1: Data given

Atomic mass of Ca = 40.08 g/mol

Atomic mass of P = 30.97 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molecular weight of Ca3(PO4)2

Molecular weight of Ca3(PO4)2 = 3*atomic mass of Ca + 2* atomic mass of P and 8* atomic mass of O

Molecular weight of Ca3(PO4)2 = 3*40.08 + 2*30.97 + 8*16.0 = 310.18 g/mol

Step 3: Calculate moles of Ca3(PO4)2 in 1350 grams

Moles Ca3(PO4)2 = mass Ca3(PO4)2 /molar mass

Moles Ca3(PO4)2 = 1350 grams / 310.18 g/mol

Moles Ca3(PO4)2 = 4.352 moles

Step 4: Calculate molecules in 1350 grams

Molecules = moles * number of Avogadro

Molecules = 4.352 moles * 6.02 * 10^23

Molecules = 2.6 *10^24 molecules

Step 5: Calculate moles Phosphorus

For 1 mol Ca3(PO4)2 we need 2 moles P

For 4.352 moles Ca3(PO4)2 we have 2*4.352 = 8.704 moles

Step 6: Calculate P atoms

Atoms P = 8.704 moles * 6.02*10^23

Atoms P = 5.24 * 10^24 P atoms

Step 7: Calculate moles Calcium in 1350 grams

For 1 mol Ca3(PO4)2 we have 3 moles Ca

For 4.352 moles we have 3*4.352 = 13.056 moles Ca

Step 8: Calculate mass of 2.1 * 10^25 molecules of Ca3(PO4)2

Moles Ca3(PO4)2 = 2.1 * 10^25 / 6.02 * 10^23

Moles Ca3(PO4)2 = 34.9 moles

Mass Ca3(PO4)2 = 34.9 moles * 310.18 g/mol

Mass Ca3(PO4)2 = 10825.3 grams

4 0

3 years ago

How many atoms are in 1.2x10^5 moles of neon?

attashe74 [19]

Answer:

7.224 × 10^28 atoms

Explanation:

The number of moles contained in a substance (n) can be calculated from this expression:

nA = n × 6.02 × 10^23 atoms

Where;

nA = number of atoms of substance

n = number of moles of substance

Avagadro's number or constant = 6.02 × 10^23 atoms

Using nA = n × 6.02 × 10^23 atoms

In this question, there are 1.2 x 10^5 moles of neon (N). The number of atoms (nA) is as follows:

nA of neon = 1.2 x 10^5 × 6.02 × 10^23

nA = 7.224 × 10^ (5 + 23)

nA = 7.224 × 10^28 atoms

The number of neon atoms in 1.2 x 10^5 is 7.224 × 10^28 atoms.

5 0

3 years ago

How much heat is released (in calories) by a sample of Pop Tarts burned in a calorimeter if the temperature of the 100 grams of

algol13

Answer:

19437 J

Explanation:

mass = 100 g

Initial Temperature = 23.5°C

Final Temperature = 70°C

Temperature change, ΔT = 70 - 23.5 = 46.5

Heat = ?

The parameters are related by the equation;

H = mc ΔT

where c = specific heat capacity = 4.18 J/g°C

H = 100 * 4.18 * 46.5 = 19437 J

7 0

3 years ago

How many valence electrons in this electron configuration 1S2 2S2 2P6 3S2

Liono4ka [1.6K]

Answer:

Explanation:

Electron Configurations

A B

Fluorine 1s2 2s2 2p5

Neon 1s2 2s2 2p6

Sodium 1s2 2s2 2p6 3s1

Magnesium 1s2 2s2 2p6 3s2

5 0

3 years ago