C-H sp2 and C=C double bond stretching bonds will disappear.
<h3>what is Infrared spectroscopy?</h3>
The examination of infrared light's interactions with molecules is known as infrared spectroscopy. It's frequently utilized to find numerous bonds and functional groups in both organic and inorganic compounds.
Each compound has a distinctive light absorption area that acts as its unique fingerprint. It can be used to identify functional groups in a molecule because the majority of them exhibit absorption bands in this range (400-1400cm-1).
This method can be used to evaluate whether the addition reaction of bromine (Br2) with 1-pentene has completed because the spectral bands for the C-H sp2 and C=C bonds will vanish.
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Answer:
It is a sigma bond
Explanation:
Chlorine has an electronic configuration of 1s2 2s2 2p6 3s2 3p5. This means that the outermost n=3 level has seven electrons. Hence one more electron is needed for the octet of outermost electrons to be achieved. As a result of this, chlorine enters into covalent bonding with another chlorine atom to form Cl2.
The outermost 3p electrons of the two chlorine atoms are now shared to form a p-p sigma bond (a single bond). Hence, the Cl2 molecule contains a sigma(single) bond between two chlorine atoms. Hence the answer written above.
Answer:
<h2>
<u>Suspension.</u></h2>
Explanation:
Since the particles of a suspension are larger than those of solutions and are insoluble, they settle to the bottom of the container over time. Therefore, suspensions need to be shaken to ensure that the solute particles are evenly distributed throughout the mixture.