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3 years ago

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A 1200 kg car is moving at 5.0 m/s east. it strikes an 1800 kg car at rest. the cars have an elastic collision and move in the e

ast or west direction. the velocity of the 1200 kg car after the collision is:

1 answer:

spayn [35]3 years ago

5 0

Velocity = (1200*5)/(1200+1800)=2

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Please help, it's an exam ://

LenaWriter [7]

Answer:

Whats the question

Explanation:

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2 years ago

An atom containing 16 protons, 31 neutrons, and 16 electrons would have an atomic mass of

Eddi Din [679]

<span>47 amu is the correct answer</span>

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2 years ago

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Un pendul este suspendat de un ax cu o tijă subțire foarte ușoară.

FromTheMoon [43]

Answer:

A)

B)

C)

Explanation:

Given that a pendulum is suspended by a shaft with a very light thin rod.

Followed by the given information: m = 100 g, I = 0.5 m, g = 9.8 m / s²

We can determine the answer to these questions using angular kinematics.

Angular kinematics is just derived from linear kinematics but in different symbols, and expressions.

Here are the formulas for angular kinematics:

θ = ωt
∆w =
L [Angular momentum] = mvr [mass × velocity × radius]

A) What is the minimum speed required for the pendulum to traverse the complete circle?

We can use the formula v = √gL derived from

B) The same question if the pendulum is suspended with a wire?

C) What is the ratio of the two calculated speeds?

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2 years ago

A T-shirt cannon can shoot a 0.085 kg T-shirt at nearly 30 m/s. The T-shirt cannon has a mass of 33 kg. If the initial net momen

IgorLugansk [536]

Answer:

Approximately $0.077\; {\rm m\cdot s^{-1}}$ (assuming that external forces on the cannon are negligible.)

Explanation:

If an object of mass $m$ is moving at a velocity of $v$ , the momentum $p$ of that object would be $p = m\, v$ .

Momentum of the t-shirt:

$\begin{aligned} p(\text{t-shirt}) &= m(\text{t-shirt}) \, v(\text{t-shirt}) \\ &= 0.085\; {\rm kg} \times 30\; {\rm m \cdot s^{-1}} \\ &= 2.55 \; {\rm kg \cdot m \cdot s^{-1}} \end{aligned}$ .

If there is no external force (gravity, friction, etc.) on this cannon, the total momentum of this system should be conserved. In other words, if $p(\text{cannon})$ denote the momentum of this cannon:

$p(\text{t-shirt}) + p(\text{cannon}) = 0$ .

$p(\text{cannon}) = -p(\text{t-shirt}) = -2.55\; {\rm kg \cdot m \cdot s^{-1}}$ .

Rewrite $p = m\, v$ to obtain $v = (p / m)$ . Since the mass of this cannon is $m(\text{cannon}) = 33\; {\rm kg}$ , the velocity of this cannon would be:

$\begin{aligned} v(\text{cannon}) &= \frac{p(\text{cannon})}{m(\text{cannon})} \\ &= \frac{-2.55\; {\rm kg \cdot m \cdot s^{-1}}}{33\; {\rm kg}} \\ &\approx 0.077\; {\rm m \cdot s^{-1}}\end{aligned}$ .

8 0

1 year ago

You are pushing a wooden crate across the floor at constant speed. You decide to turn the crate on end, reducing by half the sur

borishaifa [10]

Answer:

D. Half as great

Explanation:

Since we know that the friction force between the surface of crate and ground is given as

$F_f = \mu F_n$

so here we know that

$\mu$ = friction coefficient between two surfaces which depends on the effective contact area between two surfaces

$F_n$ = normal force due to the object

So when we turn the object on another side such that the surface area is half then the friction coefficient will become also half

So here the friction force will also reduce to half

so correct answer will be

D. Half as great

3 0

2 years ago