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oksano4ka [1.4K]
3 years ago
14

Can two negatively charged balloons move apart without ever touching why or why not

Physics
2 answers:
Nutka1998 [239]3 years ago
8 0
Yes, because electric charges have electric field surrounding them that allow them to exert forces on other objects without touching them.
Sloan [31]3 years ago
4 0

Your answer would indeed be, yes, because electric charges have electric field surrounding them that allow them to exert forces on other objects without touching them.

just took the test and got it right! Hope this helped!

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Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic colli
serious [3.7K]

Answer:

pf = 198.8 kg*m/s

θ = 46.8º N of E.

Explanation:

  • Since total momentum is conserved, and momentum is a vector, the components of the momentum along two axes perpendicular each other must be conserved too.
  • If we call the positive x- axis to the W-E direction, and the positive y-axis to the S-N direction, we can write the following equation for the initial momentum along the x-axis:

       p_{ox} = p_{oAx} + p_{oBx}  (1)

  • We can do exactly the same for the initial momentum along the y-axis:

       p_{oy} = p_{oAy} + p_{oBy}  (2)

  • The final momentum along the x-axis, since the collision is inelastic and both objects stick together after the collision, can be written as follows:

       p_{fx} =  (m_{A} + m_{B} ) * v_{fx}  (3)

  • We can repeat the process for the y-axis, as follows:

       p_{fy} =  (m_{A} + m_{B} ) * v_{fy}  (4)

  • Since (1) is equal to (3), replacing for the givens, and since p₀Bₓ = 0, we can solve for vfₓ as follows:

       v_{fx} = \frac{p_{oAx}}{(m_{A}+ m_{B)}} = \frac{m_{A}*v_{oAx} }{(m_{A}+ m_{B)}} =\frac{17.0kg*8.00m/s}{46.0kg} =  2.96 m/s (5)

  • In the same way, we can find the component of the final momentum along the y-axis, as follows:

       v_{fy} = \frac{p_{oBy}}{(m_{A}+ m_{B)}} = \frac{m_{B}*v_{oBy} }{(m_{A}+ m_{B)}} =\frac{29.0kg*5.00m/s}{46.0kg} =  3.15 m/s (6)

  • With the values of vfx and vfy, we can find the magnitude of the final speed of the two-object system, applying the Pythagorean Theorem, as follows:

      v_{f} = \sqrt{v_{fx} ^{2} + v_{fy} ^{2}} = \sqrt{(2.96m/s)^{2} + (3.15m/s)^{2}} = 4.32 m/s (7)

  • The magnitude of the final total momentum is just the product of the combined mass of both objects times the magnitude of the final speed:

       p_{f} = (m_{A} + m_{B})* v_{f}  = 46 kg * 4.32 m/s = 198.8 kg*m/s (8)

  • Finally, the angle that the final momentum vector makes with the positive x-axis, is the same that the final velocity vector makes with it.
  • We can find this angle applying the definition of tangent of an angle, as follows:

       tg \theta = \frac{v_{fy}}{v_{fx}} = \frac{3.15 m/s}{2.96m/s} = 1.06 (9)

       ⇒ θ = tg⁻¹ (1.06) = 46.8º N of E

8 0
3 years ago
A current of 17 A flows through a resistor of 10 2. What is the voltage<br> across the resistor
zhenek [66]
Ohms law V = IR

17 x 10 = 170V
5 0
3 years ago
A race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this
krok68 [10]

Answer:

add 44m/s and 22m/s then multiply it by 11

Explanation:

8 0
2 years ago
Someone please help
saul85 [17]

Based on the attached image:

  • The name of the longitude line that passes through point A is the International Date Line
  • The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
  • The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
  • Longitude 120° is B
  • Solar time at Point B is 4 pm
  • The location will correspond to any point on the same latitude as A

<h3>What are lines of longitude?</h3>

Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.

Longitude lines divide the earth into semi-circles.

Longitude lines are known as meridians and each meridian measures one arc degree of longitude.

Considering the attached image:

  • The name of the longitude line that passes through point A is the International Date Line
  • The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
  • The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
  • Longitude 120° is B
  • Solar time at Point B is 4 pm
  • the location will correspond to any point on the same latitude as A

In conclusion, longitude lines are imaginary lines and run from North to South on the earth.

Learn more about lines of longitude at: brainly.com/question/1939015

#SPJ1

8 0
2 years ago
What statement about the greenhouse effect is not true?
Nimfa-mama [501]

The so-called greenhouse effect is observed only in houses painted green, and even there, only between the hours of 2PM - 4PM local time on Thursday afternoon.

5 0
3 years ago
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