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lesantik [10]
3 years ago
11

According to the Heisenberg uncertainty principle, if the uncertainty in the speed of an electron is 3.5 × 103 m/s, the uncertai

nty in its position (in m) is at least:
Physics
1 answer:
GREYUIT [131]3 years ago
6 0

Explanation:

It is given that,

Uncertainty in the speed of an electron, \Delta v=3.5\times 10^3\ m/s

According to Heisenberg uncertainty principle,

\Delta x.\Delta p=\dfrac{h}{4\pi}

\Delta x is the uncertainty in the position of an electron

Since, \Delta p=m\Delta v

\Delta x=\dfrac{h}{4\pi.m \Delta v}

\Delta x=\dfrac{6.6\times 10^{-34}}{4\pi\times 9.1\times 10^{-31}\times 3.5\times 10^3}

\Delta x=1.64\times 10^{-8}\ m

So, the uncertainty in its position is 1.64\times 10^{-8}\ m. Hence, this is the required solution.

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A ray of light in glass strikes a water-glass interface at an angle of incidence equal to one-half the critical angle for that i
fomenos

Answer:

Explanation:

There will not be any internal reflection . it will be only refraction

critical angle = θ

Sinθ = 1 / μg

μg = 1.43 / 1.33 =

Sinθ = 1.33 / 1.43

= .93

θ = 68.44

angle of incidence i = 68.44 / 2

= 34.22

Sin i / Sin r = μw = 1.33 / 1.43  

= .93

sin 34.22  / sinθ₁ = .93 , θ₁ is angle of refraction.

sinθ₁ = sin 34.22 / .93

= .5623 / .93

= .6047

θ₁ = 37 degree Ans

5 0
3 years ago
Which option is a force?<br> O A. Mass<br> O B. Velocity<br> O C. Acceleration<br> O D. Weight
olga_2 [115]

Answer:

Weight is a force.

Explanation:

Force acting on an object is defined in terms of mass and its acceleration. Its mathematical force is given by

F = ma

Weight of an object is force that the Earth exerts on an object. It can be given by the formula as follows :

W = mg

g is acceleration due to gravity on the surface of earth

Hence, the correct option is (d).

6 0
3 years ago
A rock is thrown down with an initial speed of 25.3 m/s from a bridge to the water below. It takes 2.29 s for the rock to hit th
Rzqust [24]
<h2>Height of bridge is 83.66 m</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 25.3 m/s

        Acceleration, a = 9.81 m/s²  

        Time, t = 2.29 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 25.3 x 2.29 + 0.5 x 9.81 x 2.29²

                      s = 83.66 m

      Height of bridge is 83.66 m

7 0
3 years ago
A straight segment of wire 35.0 cm long carrying a current of 2.60 A is in a uniform magnetic field. The segment makes an angle
den301095 [7]

Answer:

Magnetic field, B = 0.275 T

Explanation:

Given that,

Length of the wire, L = 35 cm = 0.35 m

Current carried in the wire, I = 2.6 A

The segment makes an angle of 53∘ with the direction of the magnetic field, \theta=53^{\circ}

Magnetic force, F = 0.2 N

To find,

The magnitude of the magnetic field.

Solution,

The magnetic force acting on the wire is given by :

F=ILBsin\theta

\theta is the angle between the length of wire and the magnetic field.

0.2=2.6\times 0.35\times B\times sin(53)

B = 0.275 T

Therefore, the magnitude of the magnetic field is 0.275 T. Hence, this is the required solution.

5 0
3 years ago
The force of magnitude F acts along the edge of the triangular plate. Determine the moment of F about point O. Find the general
Sever21 [200]

Answer:

The moment is 81.102 k N-m in clockwise.

Explanation:

Given that,

Force = 260 N

Side = 580 mm

Distance h = 370 mm

According to figure,

Position of each point

O=(0,0)

A=(0,-b)

B=(h,0)

We need to calculate the position vector of AB

\bar{AB}=(h-0)i+(0-(-b))j

\bar{AB}=hi+bj

We need to calculate the unit vector along AB

u_{AB}=\dfrac{\bar{AB}}{|\bar{AB}|}

u_{AB}=\dfrac{h\hat{i}+b\hat{j}}{\sqrt{h^2+b^2}}

We need to calculate the force acting along the edge

\hat{F}=F(u_{AB})

\hat{F}=F(\dfrac{h\hat{i}+b\hat{j}}{\sqrt{h^2+b^2}})

We need to calculate the net moment

\hat{M}=\hat{F}\times OA

Put the value into the formula

\hat{M}=F(\dfrac{h\hat{i}+b\hat{j}}{\sqrt{h^2+b^2}})\times(-b\hat{j})

\hat{M}=\dfrac{F}{\sqrt{h^2+b^2}}((h\hat{i}+b\hat{j})\times(-b\hat{j}))

\hat{M}=\dfrac{F}{\sqrt{h^2+b^2}}(-bh\hat{k})

\hat{M}=-\dfrac{bhF}{\sqrt{h^2+b^2}}

Put the value into the formula

\hat{M}=-\dfrac{580\times10^{-3}\times370\times10^{-3}\times260}{\sqrt{(370\times10^{-3})^2+(580\times10^{-3})^2}}

\hat{M}=-81.102\ \hat{k}\ N-m

Negative sign shows the moment is in clockwise.

Hence, The moment is 81.102 k N-m in clockwise.

5 0
3 years ago
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