All categories

3 years ago

A bar of metal had a volume of 4.5 cm^3 and a mass of 33 g. what is the density of the metal?

Physics

1 answer:

Schach [20]3 years ago

7 0

Density is defined as the ratio of mass and volume of an object

$Density = \frac{mass}{volume}$

mass = 33 g

$Volume = 4.5 cm^3$

Now we can use the formula of density

$Density = \frac{33}{4.5}$

$Density = 7.33 \frac{g}{cm^3}$

You might be interested in

ear the end of a marathon race, the first two runners are separated by a distance of 45.0 m. The front runner has a velocity of

sesenic [268]

Answer:

a) $V_{2/1}=0.8m/s$

b) The second runner will win

c) d = 10.54m

Explanation:

For part (a):

$V_{2/1} = V_{2} - V_{1} = 0.8m/s$

For part (b) we will calculate the amount of time that takes both runners to cross the finish line:

$t_{1} = \frac{X_{1}}{V_{1}}=\frac{250}{3.45}=72.46s$

$t_{2} = \frac{X_{2}}{V_{2}}=\frac{250+45}{4.25}=69.41s$

Since it takes less time to the second runner to cross the finish line, we can say the she won the race.

For part (c), we know how much time it takes the second runner to win, so we just need the position of the first runner in that moment:

X1 = V1*t2 = 239.46m Since the finish line was 250m away:

d = 250m - 239.46m = 10.54m

6 0

3 years ago

Read 2 more answers

It is now 9:11 a.m. but when the bell rings at 9:12 a.m. Susie will be late for Mrs. Garner's U.S. History class for the 3rd tim

GaryK [48]

Answer:

3.1 m/s

Explanation:

The total distance she has to run is the addition of the three lengths:

47 + 63 + 76 = 186 meters.

She needs to cover it one minute (60 seconds). Therefore her speed must be:

186 m / 60 s = 3.1 m/s

6 0

3 years ago

Determine the velocity that a car should have while traveling around a frictionless curve of radius 100m and that is banked 20 d

alex41 [277]

Answer:

$v=18.89\frac{m}{s}$

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

$\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)$

Solving N from (2) and replacing in (1):

$N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c$

The centripetal acceleration is given by:

$a_c=\frac{v^2}{r}$

Replacing and solving for v:

$gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}$

4 0

3 years ago

The energy required to ionize magnesium is 738 kj/mol. What minimum frequency of light is required to ionize magnesium

Cerrena [4.2K]

Answer:

The minimum frequency required to ionize the photon is 111.31 × $10^{37}$ Hertz

Given:

Energy = 378 $\frac{kJ}{mol}$

To find:

Minimum frequency of light required to ionize magnesium = ?

Formula used:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

Solution:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

738 × $10^{3}$ = 6.63 × $10^{-34}$ × v

v = 111.31 × $10^{37}$ Hertz

The minimum frequency required to ionize the photon is 111.31 × $10^{37}$ Hertz

7 0

3 years ago

Read 2 more answers

a steel ball rolls horizontally off the edge of a tabletop that is 1.0 m high. it strikes the floor at a point 2.0 m horizontall

Sauron [17]

The ball in the air is for 0.319 sec.

The horizontal pace of a projectile is regular (in no way converting in value), and there's a vertical acceleration because of gravity; its cost is 9.8 m/s/s, down, The vertical speed of a projectile changes via nine.8 m/s every second, The horizontal motion of a projectile is impartial to its vertical movement.

Projectile motion is a form of motion experienced with the aid of an object or particle that is projected in a gravitational field, such as from Earth's floor, and movements alongside a curved route below the action of gravity best.

Projectile motion is the movement of an object thrown (projected) into the air. After the initial force that launches the item, it most effectively reports the pressure of gravity. The object is known as a projectile, and its route is called its trajectory.

Calculate:-

H = ut + 1/2 gt²

Since the vertical initial velocity is 0.

H = 0 +gt²

t = $\sqrt{ \frac{H}{g}$

= $\sqrt{ \frac{1}{9.8}$

= 0.319 sec.

Learn more about projectile motion here:-brainly.com/question/10680035

#SPJ4

6 0

1 year ago