A 5.0 kg block is placed on a 30 degree friction-less incline on the surface of earth. What will be the acceleration of the bloc
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The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, will be s = 9.5 m.
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
These equations link five kinematic variables:
Displacement (denoted by Δx)
Initial Velocity v0
Final Velocity denoted by v
Time interval (denoted by t)
Constant acceleration (denoted by a)
These equations define motion at either constant velocity or at constant acceleration. Because kinematics equations are only applicable at a constant acceleration or a constant speed, we cannot use them if either of the two is changing.
v = u + at
0 = 9.5 + a (2)
a = - 9.5 /2 m/
=
+ 2as
0 = + 2* (- 9.5 /2) * s
- = - 9.5 s
s = 9.5 m
To learn more about kinematics here
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By definition, centripetal acceleration is given by:
Where,
v: tangential disk speed
r: disk radius
Substituting values in the given equation we have:
Rounding the result we have:
Answer:
The centripetal acceleration of the disc edge in m/s^2 is: