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xenn [34]
3 years ago
12

You are asked to calculate an object's velocity, in order to do so you must know the object's ?

Physics
1 answer:
elixir [45]3 years ago
5 0
There are so many answers. It depends on which field of physics you are working on.
You could calculate velocity from momentum or kinetic energy knowing also the object's mass for example.
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Newton’s Second Law of motion defines force in terms of mass and acceleration, F= ma. Which of the following is false? The term
NikAS [45]

Answer:

The forces creating the net force must lie in the same direction.

Explanation:

newton's second law states that the net force acting on the body is equal to the product of mass and the acceleration of the body.

If there are several forces acting on the body in different directions, then we have to find teh net force by using the vector sum and then find the acceleration.

It is not necessary that all the forces acting in the same direction.

if they are in different directions then we have to find the net force by t=using the formula for the vector sum.

5 0
3 years ago
What is trapezord mean
igor_vitrenko [27]
A quadrilateral with only one pair of parallel sides.
<span>a small carpal bone in the base of the hand, articulating with the metacarpal of the index finger.
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5 0
3 years ago
Electromagnetic radiation consists of particles called:
Westkost [7]

Photons are particles of electromagnetic radiation.

8 0
3 years ago
a sealed cylinder contains a sample of ideal gas at a pressure of 2.0 atm. The rms speed of the molecules is v0. If the rms spee
fredd [130]

Answer:

P_2 = 1.62 atm

Explanation:

We know the formula for the rms speed of the ideal gas is  given by

v_{rsm}=\sqrt{\frac{3PV}{m} }

P= pressure of the surrounding

V= volume of the vessel

m= mass of the gas

Now, From this formula rms speed (v_rms) is directly proportional to square root is pressure.

Then  

\frac{v_{rsm,1}}{v_{rsm,2}} =\sqrt{\frac{P_1}{P_2} }

given that v_rsm,1= v0

and v_rsm,2=0.9v0

putting these values we get

\frac{v0}{0.9v0} =\sqrt{\frac{2}{P_2} }

P_2 = 1.62 atm

8 0
3 years ago
Read 2 more answers
A test charge is placed at a distance of 3.5 meters from a charge of 8.7 × 10-9 coulombs. What is the electric field strength at
zavuch27 [327]
In order to calculate the electric field strength, we may use the formula:
E = kQ/d²
Where Q is the charge and d is the distance between the charge and the test charge. Substituting the values into the equation:
E = (9 x 10⁹)(8.7 x 10⁻⁹) / (3.5²)
E = 6.39 Newtons per coulomb

Therefore, the answer is 6.4 Newtons/coulomb
8 0
3 years ago
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