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Hitman42 [59]
4 years ago
9

A sinusoidal traveling wave is generated on a string by an oscillating source that completes 116 cycles per minute. What is the

wavelength of the wave if individual crests are observed to travel 11.0 m in 1.50 min?
Physics
1 answer:
slava [35]4 years ago
6 0

Answer:

\lambda =6.32\ cm

Explanation:

given,

number of cycle complete (f) = 116 cycles per minute

wavelength observed at 11 m in 1.5 m.

v = \dfrac{distance}{time}

v = \dfrac{11}{1.5}

v = 7.33 m/s

\lambda = \dfrac{v}{f}

\lambda = \dfrac{7.33}{116}

\lambda =0.0632\ m

\lambda =6.32\ cm

The wavelength of the wave is equal to \lambda =6.32\ cm

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3 years ago
As a system increases in volume, it absorbs 59.0 J of energy in the form of heat from the surroundings. The piston is working ag
Zepler [3.9K]

Answer:

The initial volume of the system is 2.7 L

Explanation:

The change in internal energy is given by;

ΔU = Q - W

where;

Q is the heat absorb from the surrounding

W is the work done by the system

Given;

ΔU  = -107.6 J

Q = 59 J

W = ?

W = Q- ΔU

W = 59J - (-107.6)

W = 166.6 J

Work done is given by;

W = PΔV

W = P(V₂ - V₁)

101.325 Joules = 1 L.atm

166.6 Joules  = ?

= 1.644 L.atm

1.644 L.atm = 0.543 atm(57.7L - V₁)

57.7L - V₁ = (1.644 L.atm) / (0.543 atm)

57.7L - V₁ = 3.0 L

V₁ = 57.7L - 3.0 L

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3 years ago
A block is at rest. The coefficients of static and kinetic friction are s = 0.81 and k = 0.69, respectively. The acceleration of
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Answer:

Explanation:

a ) The angle required = angle of repose = θ

Tanθ = .81

θ = 39⁰

b ) when angle of incline θ = 44

Net force on the block = mg sinθ - μ mg cosθ where μ is coefficient of kinetic friction

acceleration = gsinθ - μ g cosθ

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Using a scale diagram, calculate the resultant force acting on a sailing boat when an easterly wind provides 2, point, 50, k, N,
EastWind [94]

Answer:

F = 3.6 kN, direction is 9.6º to the North - East

Explanation:

The force is a vector, so one method to find the solution is to work with the components of the vector as scalars and then construct the resulting vector.

Let's use trigonometry to find the component of the forces, let's use a reference frame where the x-axis coincides with the East and the y-axis coincides with the North.

Wind

X axis

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Tide

         cos 30 = F₂ₓ / F₂

         sin 30 = F_{2y} / F₂

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the resultant force is

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        Fₓ = 2.50 +1.039

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to find the vector we use the Pythagorean theorem

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         F = \sqrt{ 3.539^2 + 0.600^2 }

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the address is

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         θ = tan⁻¹ \frac{F_y}{F_x}

         θ = tan⁻¹  \frac{0.6}{3.539}0.6 / 3.539

         θ = 9.6º

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