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zhenek [66]
3 years ago
15

Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases. (Assume that centra

l areas are centered at t = 0. Round your answers to three decimal places.)
a. Central area = 0.95, df = 10
b. Central area = 0.95, df = 20
c. Central area = 0.99, df = 20
d. Central area = 0.99, df = 60
e. Upper-tail area = 0.01, df = 30
f. Lower-tail area = 0.025, df = 5
Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:

Step-by-step explanation:

a) this involves 2 tails

The critical value is determined from the t distribution table.

α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Looking at 0.975 with df 10

The critical value is 2.228

b) α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Looking at 0.975 with df 20

The critical value is 2.086

c) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Looking at 0.995 with df 20

The critical value is 2.845

d) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Looking at 0.995 with df 60

The critical value is 2.660

e) 1 - α = 1 - 0.01 = 0.99

Looking at 0.99 with df 10

The critical value is 2.764

f) 1 - α = 1 - 0.025 = 0.975

Looking at 0.975 with df 5

The critical value is 2.571

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each year francesca earns a salary of 2% higher than her previous years salary. In her first 5 years at this job, she earned a t
Luda [366]

Answer:

$36,027.9

Step-by-step explanation:

Lets say her salary in the first year is s1. So, in the second year her salary will be 2% higher than x, this is, s1 + s1*0.02, so:

s2 = s1 + 0.02s1 = 1.02s1

Then in year 3 it will be s2 plus a 0.02 increase:

s3 = s2 + 0.02s2 = 1.02(s2) = 1.02 (1.02 s1) = 1.02^2(s1)

Then the same for s4: s3 salary plus the increase.

s4 = s3 + 0.02s3 = 1.02(s3) = 1.02 (1.02 s2) = 1.02(1.02*1.02 s1) =1.02^3(s1)

Finally for the 5th monts:

s5 = 1.02(s4) = 1.02^4(s1)

We know that s1+s2+s3+s4+s5 = 187,345

Lets replace all the salaries by its value depending on s1

s1 + 1.02s1 + 1.02^2(s1) + 1.02^3(s1) + 1.02^4(s1) = 187,345

We can add to the first term a s1^0 as it is eqaul to 1

s1 + 1.02s1 + 1.02^2(s1) + 1.02^3(s1) + 1.02^4(s1) = 187,345

Lets get 1s1 out as common factor:

s1 (1 + 1.02^1 + 1.02^2 + 1.02^3 + 1.02^4) = 187,345

s1 *5.20 = 187,345

Divide both sides by 5.20

s1 = 36,027.9

So, her salary in the 1st month was approximately $36,027.9

4 0
3 years ago
Read 2 more answers
1. What number is 59% of $45?
Montano1993 [528]

Answer:

It is $26.55

Step-by-step explanation:

=59% of 45

=59/100*45

We get

=59*45/100

=2655/100

=$26.55

4 0
3 years ago
Read 2 more answers
Pleases help and thank you
Furkat [3]

Answer:

B is answer

Step-by-step explanation:

24/(2+2)

24/4

6

6 0
3 years ago
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