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Zielflug [23.3K]
3 years ago
10

During a test crash an airbag inflates to stop a dummy's forward motion. the dummy's mass is 75kg. If the net force on the dummy

is 825n toward the rear of the car , what is the dummy's deceleration.
Physics
1 answer:
Black_prince [1.1K]3 years ago
4 0
F=ma
a=F/m
=825N/75kg
=825kg*m/75kg*s^2
=11m/s^2 in the direction of the force (ans)
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A spinning disc rotating at 130 rev/min slows and stops 31 s later. how many revolutions did the disc make during this time?
gayaneshka [121]
F = 130 revs/min = 130/60 revs/s = 13/6 revs/s
t = 31s
wi = 2πf = 2π × 13/6 = 13π/3 rads/s
wf = 0 rads/s = wi + at
a = -wi/t = -13π/3 × 1/31 = -13π/93 rads/s²
wf² - wi² = 2a∅
-169π²/9 rads²/s² = 2 × -13π/93 rads/s² × ∅
∅ = 1209π/18 rads
n = ∅/2π = (1209π/18)/(2π) = 1209/36 ≈ 33.5833 revolutions.
3 0
2 years ago
Contrary to popular belief, a ski jumper does not achieve a large amount of "air" when doing a jump (less than 6 feet). This is
Elina [12.6K]

Answer:

The vertical distance that the ski jumper fell is 417.45 m.

Explanation:

Given;

initial horizontal velocity of the jumper, V_x = 26 m/s

horizontal distance of the jumper, dx = 240 m

The time of the motion is given by;

dx = Vₓt

t = dx / Vₓ

t = 240 / 26

t = 9.23 s

The vertical distance traveled by the diver is given by;

d_y = V_yt + \frac{1}{2}gt^2

initial vertical velocity, V_y, = 0

d_y =  \frac{1}{2}gt^2\\\\d_y = \frac{1}{2}(9.8)(9.23)^2\\\\d_y = 417.45 \ m

Therefore, the vertical distance that the ski jumper fell is 417.45 m.

6 0
3 years ago
1. boiling point of water
melomori [17]

Answer:

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5 0
2 years ago
A loudspeaker produces a sound wave of frequency 50hz.
viktelen [127]
Hey mate
Here is your answer
Option A)
Explanation:
The larger the amplitude of the waves, the louder the sound. Pitch (frequency) – shown by the spacing of the waves displayed. The closer together the waves are, the higher the pitch of the sound.
Pls mark as brainliest
3 0
2 years ago
A boat is traveling at an initial velocity of 2.7 meters per second in the positive direction. It accelerates at a rate of 0.15
cupoosta [38]

Answer:

\boxed {\boxed {\sf 4.5 \ m/s \ in \ the  \ positive \ direction}}

Explanation:

We are asked to find the final velocity of the boat.

We are given the initial velocity, acceleration, and time. Therefore, we will use the following kinematic equation.

v_f= v_i + at

The initial velocity is 2.7 meters per second. The acceleration is 0.15 meters per second squared. The time is 12 seconds.

  • v_i= 2.7 m/s
  • a= 0.15 m/s²
  • t= 12 s

Substitute the values into the formula.

v_f = 2.7 \ m/s + (0.15 \ m/s^2)(12 \ s)

Multiply the numbers in parentheses.

v_f= 2.7 \ m/s + (0.15 \ m/s/s * 12 \ s)

v_f = 2.7 \ m/s + (0.15 \ m/s *12)

\v_f=2.7 \ m/s + (1.8 \ m/s)v_f=2.7 \ m/s + (1.8 \ m/s)

Add.

v_f=4.5 \ m/s

The final velocity of the boat is <u>4.5 meters per second in the positive direction.</u>

5 0
2 years ago
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