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Degger [83]
3 years ago
15

Calculate the half-life of different radioactive sources.

Chemistry
1 answer:
otez555 [7]3 years ago
7 0
The rate at which a radioactive<span> isotope decays is measured in </span>half-life. The termhalf-life<span> is defined as the time it takes for one-</span>half<span> of the atoms of a </span>radioactive material<span> to disintegrate. </span>Half-lives<span> for </span>various radioisotopes<span> can range from a few microseconds to billions of years.
</span>.
back at it again with that answer
.
zane
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3. 4 g of a nonelectrolyte dissolved in 78. 3 g of water produces a solution that freezes at −4. 5∘c. what is the molar mass of
enyata [817]

3. 4 g of a nonelectrolyte dissolved in 78. 3 g of water produces a solution. The molar mass of the solute will be 17.94.

<h3>What is molar mass?</h3>

Molar mass of a substance is its mass in grams in per mole of  a solution.

Freezing point: Freezing point of a substance is a temperature at which a liquid starts to solidify.

Depression in the freezing point can be calculated

[Depression in freezing point of pure solvent—Freezing point of solution] =[(0) - (-4.5)] °C =4.5 °C

molar mass = Number of moles of solute m / Mass of solvent in Kg

3.4g / M x 1/ 0.0783 kg  = 43.42

Substitute AT by 4.5°C , Kr by 1.86 °C/m, and m by 43.42 m in equation (1) as follows:

1.86 x 43.42 / 4.5 = 17.94

Therefore, molar mass of solute to be 17.94.

To learn more about molar mass, refer to the link:

brainly.com/question/22997914

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4 0
2 years ago
The combustion of gasoline produces carbon dioxide and water. assume gasoline to be pure octane (c8h18) and calculate how many k
IgorC [24]
<span>Answer: 2 C8H18 + 25 O2 => 16 CO2 + 18 H2O 1.0 kg = 1000 g C8H18 = 1000 g / 114.2293 g/mole = 8.75 moles C8H18 8.75 moles C8H18 produce (16/2) (8.75) = 70 moles CO2 70 moles CO2 = (70 moles) (44.0096 g/mole) = 3081 g CO2 = 3.1 kg CO2</span>
7 0
4 years ago
Calculate the molar concentration of the polycyclic aromatic hydrocarbon (pah), anthracene (178.23 g/mol), that was found in a w
tester [92]

solution:

Calculate the molar concentration of the polycyclic aromatic hydrocarbon(PHA)(178.23g/mol),that was found in a well water sample at a concentration of 6.21ppb.Assume the density of the water is 1.00mg/mLppb corresponds to 1\mu g in 1L of sample \\the 6.21 ppb is 6.21\mu g in 1L of sample\\6.21\mu g PHA\times\frac{1mg PHA}{1000\mu g PHA}\times\frac{1g PHA}{1000\mu mg PHA}\times\frac{1mol. PHA}{178.23g PHA}\\3.48\times10^-8mol PHA\\and if we have 1L of solution\\m=\frac{moles}{v(L)}=\frac{3.48\times10^-8mol}{1L}\\3.348\times^10-8 M

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3 years ago
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What are the 5 parts of an atom?
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Electrons

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mesons

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Label B-L in the diagram below
Debora [2.8K]

Answer:

B. Polar Easterlies

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D. Prevailing westerlies

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Explanation:

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