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3 years ago

Which statement is true about a polarized object?

Physics

2 answers:

agasfer [191]3 years ago

8 0

A polar substance has regions that are positive and negative, but there are no electrons exchanged. so the best answer is 5

GREYUIT [131]3 years ago

3 0

Answer: Option (3) is the correct answer.

Explanation:

When an object is polarized then it means that if a negatively charged object is brought near a neutral atom then a positive charge will develop on the neutral object near the area of contact.

Whereas a negative charge will develop on the opposite side neutral object which is not in contact with the negatively charged object.

Hence, in a polarized object there are equal number of both positive and negative charges.

Thus, we can conclude that the statement number of positive and negative charges can be the same, is true about a polarized object.

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You are trying to determine the specific gravity of a solid object that floats in water. If m is the mass of your object, mS is

Alisiya [41]

Answer:

Specific Gravity = m/[m(s)-m(os)]

Explanation:

Specific gravity, also called relative density, is the ratio of the density of a substance to the density of a reference substance. By this definition we need to find out the ratio of density of the object of mass m to the density of the surrounding liquid.

m = mass of the object

Weight in air

W (air) = mg, where g is the gravitational acceleration

Weight with submerged with only one mass

m(s)g + Fb = mg + m(b)g, consider this to be equation 1

where Fb is the buoyancy force

Weight with submerged with both masses

m(os)g + Fb’ = mg + m(b)g, consider this to be equation 2

equation 1 – equation 2 would give us

m(s)g – m(os)g = Fb’ – Fb

where Fb = D x V x g, where D is the density of the liquid the object is submerged in, g is the force of gravity and V is the submerged volume of the object

m(s)g – m(os)g = D(l) x V x g

m(s) – m(os) = D(l) x V

we know that Mass = Density x V, which in our case would be, D(b) x V, which also means

V = Mass/D(b), where D(b) is the density of the mass

Substituting V into the above equation we get

m(s) – m(os) = [D(l) x m)/ D(b)]

Rearranging to get the ratio of density of object to the density of liquid

D(b)/D(l) = m/[m(s)-m(os)], where D(b)/D(l) denotes the specific gravity

8 0

3 years ago

What would you do to improve the precision of an experiment?

GenaCL600 [577]

Explanation:

Precision represents that how close the different measurements of the sample one take are to one another.

One can increase the precision in lab by paying attention to each and every detail.
Usage of the equipment properly and also increasing the sample size.
Ensuring that the equipment is calibrated properly. They should be clean and functioning. Using equipment which is not functioning correctly can cause results to swing wildly and also bits of the debris stuck to the equipment can influence the measurements of the mass and the volume.
Each measurement must be taken multiple times, especially if experiments in which combining of the substances in specific amounts is involved.

5 0

3 years ago

Read 2 more answers

As a result of photosynthesis is the production of sugar molecules known as what?

Bezzdna [24]

Answer:

Glucose

Explanation:

4 0

3 years ago

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A scientist observes an increase in the rate at which water moves from the hydrosphere to the atmosphere at a particular locatio

Musya8 [376]

At a particular location, when an an increase in the rate at which water moves from the hydrosphere to the atmosphere, an increase in humidity is expected at that location. The term "humidity" generally refers to the amount of water vapor in the atmosphere.

7 0

3 years ago

What is the frequency of a wave having a period equal to 18 seconds

Ivanshal [37]

Explanation:

The time taken by a wave crest to travel a distance equal to the length of wave is known as wave period.

The relation between wave period and frequency is as follows.

T = \frac{1}{f}T=

where, T = time period

f = frequency

It is given that wave period is 18 seconds. Therefore, calculate the wave period as follows.

T = \frac{1}{f}T=

or, f = \frac{1}{T}f=

= \frac{1}{18 sec}

18sec

= 0.055 per second (1cycle per second = 1 Hertz)

or, f = 5.5 \times 10^{-2} hertz5.5×10 −2 hertz

<h3>Thus, we can conclude that the frequency of the wave is 5.5 \times 10^{-2} hertz5.5×10 −2 hertz .</h3>

3 0

3 years ago