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Pavlova-9 [17]
3 years ago
7

Why does the frequency of a wave increase as the wavelength decreases?

Physics
2 answers:
lubasha [3.4K]3 years ago
8 0
Correct option A

The wave speed remains constant.So if the frequency increases then wavelength increases and if frequency decreases then wavelength increases to maintain the constant wave speed.

Hope This Helps You!
Mashutka [201]3 years ago
3 0

Answer: The correct answer is " because the wave speed remains constant".

Explanation:

The expression of the wavelength in terms of the frequency is as follows;

\lambda =\frac{c}{f}

Here, c is the speed of the light, f is the frequency of the wave and \lambda is the wavelength of the wave.

The wavelength of the wave is inversely proportional to the frequency of the wave as the speed of the wave remains constant.

If the wavelength of the wave decreases then the frequency of the wave increases.

Therefore, the frequency of a wave increases as the wavelength decreases because the wave speed remains constant.

The correct option is (A).

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An air-track glider attached to a spring oscillates between the 10.0 cm mark and the 61.0 cm mark on the track. The glider compl
Novosadov [1.4K]

Answer:

T = 2.82 seconds.

The frequency \mathbf{f = 0.36 \ Hz}

Amplitude A = 25.5 cm

The maximum speed of the glider is \mathbf{v = 56.87 \ rad/s}

Explanation:

Given that:

the time taken for 11 oscillations is 31 seconds ;

SO, the time taken for one oscillation is :

T = \frac{31}{11}

T = 2.82 seconds.

The formula for calculating frequency can be expressed as :

f = \frac{1}{T}

f = \frac{1}{2.82}

\mathbf{f = 0.36 \ Hz}

The amplitude is determined by using the formula:

A = \frac{d}{2}

The limits that the spring makes the oscillations are from 10 cm to 61 cm.

The distance of the glider is, d = (61 - 10 )cm = 51 cm

Replacing 51 for d in the above equation

A = \frac{51}{2}

A = 25.5 cm

The maximum speed of the glider is:

v = A \omega

where ;

\omega = \frac{2 \pi}{T}

\omega = \frac{2 \pi}{2.82}

\omega = 2.23 \ rad/s

v = A \omega

v = 25.5 *2.23

\mathbf{v = 56.87 \ rad/s}

3 0
3 years ago
At 9:13AM a car is traveling at 35 miles per hour. Two minutes later, the car istraveling at 85 miles per hour. Prove that are s
andreyandreev [35.5K]

Answer:

There is at least one instant which instantaneous acceleration is equal to average acceleration. a = 1500\,\frac{km}{h^{2}}.

Explanation:

The average acceleration experimented by the car is:

\bar a = \frac{85\,\frac{km}{h} - 35\,\frac{km}{h} }{\frac{2}{60}\,h }

\bar a = 1500\,\frac{km}{h^{2}}

According to the Rolle's Theorem, there is at least one instant t so that instantaneous acceleration equal to average acceleration for the analyzed interval. That is to say:

v'(c) = \frac{v(\frac{2}{60} )-v(0)}{\frac{2}{60}-0}

If car is accelerating at constant rate, instantaneous acceleration coincides with average acceleration for all instant t. Then, instantaneous acceleration is:

a = 1500\,\frac{km}{h^{2}}

6 0
3 years ago
Technician A says that low compression on a single cylinder will cause an engine not to start. Technician B says that low compre
olga2289 [7]

Answer:

Technician B who says that low compression on a single cylinder will affect the engine’s cranking sound

Explanation:

if you have low compression in one cylinder, the engine will start but you'll likely experience misfires and your vehicle will run roughly.

It's only when you have no compression at all that the engine will not start.

The technician that said that low compression on a single cylinder will affect the engine’s cranking sound is correct.

8 0
3 years ago
Can anyone help me with any parts in question number 1: parallel circuit?
Leno4ka [110]
Question #1:

a).  The sketch is attached to this answer.

b).  The equivalent resistance of 30Ω and 50Ω in parallel is

1 / (1/30 + 1/50)  =  18.75 Ω

c).   I = V/R = (100/30) = (3 and 1/3) Amperes

d).  Follow the wires, and you see that the 50Ω resistor is
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on the voltmeter, is 100 volts.

e).  I = V/R
Through the 30Ω resistor:  I = 3-1/3 A
Through the 50Ω resistor:  I = 2 A

f).  In the parallel circuit, both resistors are connected
directly to the battery.  So neither resistor even knows
that the other one is there.  Each resistor sees 100 volts,
and the current through each resistor is 100/R, just as if
it were the only resistor in the circuit.

4 0
3 years ago
The skater is has a mass of 75 kg. Find the total Potential energy of the skater at the top of the ramp at 6 m.
AlekseyPX
P= mgh
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4 0
3 years ago
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