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marusya05 [52]
3 years ago
9

How many molecules are in 10 moles of Hydrogen?

Chemistry
1 answer:
vivado [14]3 years ago
8 0

Answer:3.2

Mass:32

Molecular weight: 10

Moles: 3.2

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A fruit and oatmeal bar contains 142 nutritional calories. Convert this energy to calories
Alekssandra [29.7K]
Answer is: a<span> fruit and oatmeal bar contains 142000 calories.
</span>A nutritional calorie<span>, or kilocalorie, is equal to 1000 calories.
</span>E = 142 kcal · 1000 cal/kcal.
E = 142 000 cal.
Calorie (cal)<span>, or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.
</span><span>One small calorie is approximately 4.2 joules.
</span>A calorie is a unit of energy.
8 0
3 years ago
What is the atomic number of pt-175 after it undergoes alpha decay
DanielleElmas [232]

Answer:

76

Explanation:

Alpha decay is one of the most basic forms of radioactive decay. It has an atomic mass of 4 and a proton number of two.

Undergoing an alpha decay will decrease the atomic mass by four and the atomic number by two.

In this particular question, we are particular about the atomic number. The atom has an atomic number of 78. So taking 2 off this gives 76

5 0
3 years ago
2. How does an atom of aluminum become an ion?
DENIUS [597]

Answer:

it loses 3 electrons

Explanation:

Tell me if I’m right

7 0
3 years ago
As part of a soil analysis on a plot of land, a scientist wants to determine the ammonium content using gravimetric analysis wit
jeka94

Answer:

Mass percentage of NH₄Cl = 3.54%

Mass percentage of K₂CO₃ = 1.01%

Explanation:

If a 200.0 mL aliquot produced  0.105 g of KB(C₆H₅)₄, then a 100.0 mL aliquot would produce 1/2 * 0.105 g = 0.0525 g of KB(C₆H₅)₄.

Therefore, mass of NH₄B(C₆H₅)₄ in the 100.0 ml aliquot = (0.277 - 0.0525)g = 0.2245 g

Number of moles of NH₄B(C₆H₅)₄ in 0.2245 g = 0.2245 g/ 337.27 g/mol = 0.0006656 moles

In 500 ml solution, number of moles present = 0.0006656 * 500/100 = 0.003328 moles.

From equation of the reaction; mole ratio of  NH₄⁺ and NH₄B(C₆H₅)₄ = 1:1

Similarly, mole ratio of  NH₄⁺ and NH₄Cl = 1:1

Therefore, moles of NH₄Cl in 500 ml sample = 0.003328 moles

Mass of NH₄Cl  = 0.003328 mol * 53.492 g/mol = 0.178 g

Mass percentage of NH₄Cl = (0.178/5.025) * 100% = 3.54%

Number of moles of KB(C₆H₅)₄ in 0.105 g (precipitated from 200.0 ml aliquot) = 0.105 g/ 358.33 g/mol = 0.000293 moles

In 500 ml solution, number of moles present = 0.000293 * 500/200 = 0.0007326 moles.

From equation of the reaction; mole ratio of  K⁺ and KB(C₆H₅)₄ = 1:1

Similarly, mole ratio of  K⁺ and K₂CO₃ = 2:1

Therefore, moles of K₂CO₃ in 500 ml sample = 0.0007326/2 moles =  0.0003663 moles

Mass of  K₂CO₃ = 0.0003663 mol * 138.21 g/mol = 0.05063 g

Mass percentage of K₂CO₃ = (0.05063/5.025) * 100% = 1.01%

7 0
3 years ago
The region in which an electron is likely to be found is known as a(n) ____________.
Zinaida [17]

Answer:

orbital

Explanation:

electrons are found in an orbital

3 0
3 years ago
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