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rosijanka [135]
3 years ago
15

How much volume in mL of 0.65 M HCI solution can be made by diluting 150 mL of 9.75 M HCI

Chemistry
1 answer:
Fynjy0 [20]3 years ago
5 0
150 x 9.75/ 0.65 = L
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Convert 625 mg to kg.
svetlana [45]

Answer: 0.000625

Explanation:

If you don't know, one Milligram is equivalent to 0.000001 Kilograms. Hence, we'll multiply 625 by 0.000001.

With that being said, 625 times 0.000001 will equal to 0.000625.

Don't forget to add the units.

Milogram unit ⇒ mg

Kilogram unit ⇒ kg

Finally, your grand answer is 0.000625.

<em>Please comment down below for any questions about my answer.</em>

4 0
2 years ago
Goldsmith believed that an excess of anything can lead to unhappiness.<br> True or false
aksik [14]
It is true because you can die of anything thus haveing an excess of ANYTHING can kill you and cause a family unhappiness

3 0
3 years ago
What is the density of 96 ml of a liquid that has a mass of 90.5 g?
Otrada [13]

Answer:

Density = Mass / Volume.   so,  x = 90.5 g / 96 mL ... The Density would be 0.942 g/mL

8 0
3 years ago
The chemical reaction for the formation of syngas is: CH4 + H2O -&gt; CO + 3 H2 What is the rate for the formation of hydrogen,
grin007 [14]

Answer :  The rate for the formation of hydrogen is, 1.05 M/s

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

CH_4+H_2O\rightarrow CO+3H_2

The expression for rate of reaction :

\text{Rate of disappearance of }CH_4=-\frac{d[CH_4]}{dt}

\text{Rate of disappearance of }H_2O=-\frac{d[H_2O]}{dt}

\text{Rate of formation of }CO=+\frac{d[CO]}{dt}

\text{Rate of formation of }H_2=+\frac{1}{3}\frac{d[H_2]}{dt}

The rate of reaction expression is:

\text{Rate of reaction}=-\frac{d[CH_4]}{dt}=-\frac{d[H_2O]}{dt}=+\frac{d[CO]}{dt}=+\frac{1}{3}\frac{d[H_2]}{dt}

As we are given that:

+\frac{d[CO]}{dt}=0.35M/s

Now we to determine the rate for the formation of hydrogen.

+\frac{1}{3}\frac{d[H_2]}{dt}=+\frac{d[CO]}{dt}

+\frac{1}{3}\frac{d[H_2]}{dt}=0.35M/s

\frac{d[H_2]}{dt}=3\times 0.35M/s

\frac{d[H_2]}{dt}=1.05M/s

Thus, the rate for the formation of hydrogen is, 1.05 M/s

6 0
3 years ago
Explain why different objects appear to be different colors.
Naddika [18.5K]

Answer:

Different objects appear to be different colors, because we see color by light bouncing off an object and reflecting or transmitting into our eye. The amount of light that reflects or transmits into our eye depend on the color that we will see.

5 0
2 years ago
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