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Citrus2011 [14]
2 years ago
12

A patient needs 40.0 mg of an antibiotic per kilogram of body weight each day. If the patient weighs 55 kilograms, how much anti

biotic, in milligrams, should the patient receive each day for optimal therapy?
Chemistry
1 answer:
Rzqust [24]2 years ago
4 0

Answer:

2,200 milligrams

Explanation:

40 mg per 1 kilogram means 40 times 55 which is 2,200 mg

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Determine the frequency of light with a wavelength of 4.257x10^-7cm
TEA [102]

Answer:

frequency of light is 70.47\times 10^{15} \ per\ second

Explanation:

Given

wavelength of light = 4.257\times 10^{-7}\ cm = 4.257\times 10^{-7} \times 10^{-2} \ m= 4.257\times 10^{-9}\ m

Speed of Light = 3\times 10^8 \ m/s

∴ Frequency of Light = \frac{\textrm{Speed of Light}}{\textrm{wavelength}}=\frac{3\times 10^8}{4.257\times 10^{-9}}= 70.47\times 10^{15} \ per\ second

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3 years ago
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6 0
3 years ago
What is the identity of the atom shown?
posledela

Answer:

A

Explanation:

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3 0
2 years ago
Read 2 more answers
.950 L of .420 M H2SO4 is mixed with .900 L of .260 M KOH. What concentration of sulfuric acid remains after neutralization?
kipiarov [429]
H₂SO₄:

V=0,95L
Cm=0,420mol/L

n = CmV = 0,42mol/L * 0,95L = 0,399mol

KOH:

V=0,9L
Cm=0,26mol/L

n = CmV = 0,26mol/L * 0,9L = 0,234mol

H₂SO₄            +           2KOH ⇒ K₂SO₄ + 2H₂O
1mol                :           2mol
0,399mol         :           0,234mol
                                    limiting reagent
reamins: 0,399mol - 0,117mol = 0,282mol

n = 0,282mol
V = 0,950L + 0,900L = 1,85L

Cm = n / V = 0,282mol / 1,85L ≈ 0,152M
3 0
3 years ago
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