Question

An unknown substance has a mass of 14.7 g . When the substance absorbs 1.323×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to 45.0 ∘C . What is the most likely identity of the substance?
A. aluminum 0.903
B. iron 0.449
C. water 4.184
D. silver 0.235
E. copper 0.385
F. ethanol 2.42

Answer 1

The correct answer of the given question above would be option B. IRON 0.449. Based on the given details above about an unknown substance that has a mass of 14.7 g and  the substance absorbs 1.323×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to45.0 ∘C, most likely, the substance is IRON. Hope this answers the question.

Answer 2

Answer : The correct option is, (B) iron 0.449

Explanation :

Formula used :

$Q=m\times c\times \Delta T\\\\Q=m\times c\times (T_2-T_1)$

where,

Q = heat absorb = $1.323\times 10^2J$

m = mass of substance = 14.7 g

c = specific heat of substance = ?

$\Delta T$ = change in temperature

$T_1$ = initial temperature = $25^oC$

$T_2$ = final temperature = $45^oC$

Now put all the given value in the above formula, we get:

$1.323\times 10^2J=14.7g\times c\times (45-25)^oC$

$c=0.45J/g^oC$

Form the value of specific heat of substance, we conclude that the metal used in this was iron.

Therefore, the correct option is (B) iron 0.449