All categories

3 years ago

So lost plz help I don’t understand this chemsitry stuff at all and no one will help me

Chemistry

1 answer:

liubo4ka [24]3 years ago

7 0

After careful deliberation, I took the opportunity to find the answers for you.

Answers:
1) _2_Al + _6_HC2H3O2 ->_2_Al(C2H3O2)3 + _3_H2
3) _1_Fe + _2_HBr -> _1_H2 + _1_FeBr2
5) _2_NaOH + _1_ H2SO4 -> _1_Na2SO4 + _2_H2O
7) _2_N2O -> _2_N2 + _1_ O2
9) _1_P4O6 + _2_O2 -> _1_P4O10
11) _2_Mg + _2_CH3COOH -> _2_Mg(CH3COO)2 + _1_H2
13) _2_Al3 + _18_HCl -> _9_H2 + _6_AlCl3
15) _4_KOH + _2_H2SO4 -> _4_H2O + _2_K2SO4
17) _2_NH3 -> _1_N2 + _3_H2
19) _2_SO2 + _1_O2 -> _2_SO3

DONE! *breathes heavily* Alright, after like 30 minutes, these are the answers for your problem.

Hope this helps! :)

You might be interested in

Why is it difficult to classify dissolving as simply a physical or a chemical change? (1 point)

Likurg_2 [28]

The correct answer is:Some substances keep the same molecular structure when they break down, and others do not.

Some substances change their form when they dissolve and some do not. Dissolution can sometimes be regarded as a sort of reaction between a chemical substance and water.

Usually, we can consider dissolution of a substance in water as a sort of chemical reaction for some substances. For instance, an ionic substance interacts with water to form ions. similarly, some salts become hydrolysed in water and give acidic/basic solutions as result of that.

However, some substances do not interact with water upon dissolution. They rather remain as molecular entities because they are not composed of ions.

We can see that some substances keep the same molecular structure when they break down, and others do not keep the same molecular structure when they dissolve hence it is difficult to classify dissolving as a physical or a chemical change.

brainly.com/question/1161517

6 0

3 years ago

Read 2 more answers

The electron configurations of two unknown elements X and Y are shown.

Svetllana [295]

X: 1S²2S²2P⁶

Y: 1S²2S²2P⁶3S²3P⁶

The statement which is most likely correct about the two elements is

They will not react because both have a complete outermost shell and are stable.

Explanation

The P orbital can hold a maximum of 6 electrons,therefore the 2P orbital for x and 3P orbital for Y which are outermost subshell are fully filled .

This make element Y and x stable since they cannot react either by gaining or losing electrons.

6 0

4 years ago

Read 2 more answers

How many formula units are in 9.3 g of alumina (Al2O3)?

Arada [10]

We need more information

8 0

3 years ago

What is the symbol for an atom containing 20 protons and 22 neutrons?

olya-2409 [2.1K]

It is an isotope of Calcium, which has the symbol Ca

6 0

3 years ago

Read 2 more answers

Commercial hydrochloric acid (HCl) is typically labeled as being 38.0 % (weight %). The density of HCl is 1.19 g/mL. a) What is

Strike441 [17]

Answer:

For a: The molarity of commercial HCl solution is 12.39 M.

For b: The molality of commercial HCl solution is 16.79 m.

For c: The volume of commercial HCl solution needed is 2.42 L.

Explanation:

We are given:

Mass % of commercial HCl solution = 38 %

This means that 38 grams of HCl is present in 100 grams of solution.

To calculate the volume of solution, we use the equation:

$Density=\frac{Mass}{Volume}$

Density of HCl solution = 1.19 g/mL

Mass of solution = 100 g

Putting values in above equation:

$1.19g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=84.034mL$

For a:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = ?

Molar mass of HCl = 36.5 g/mol

Volume of solution = 84.034 mL

Mass of HCl = 38 g

Putting values in above equation, we get:

$\text{Molality of commercial HCl solution}=\frac{38\times 1000}{36.5\times 84.034}\\\\\text{Molality of commercial HCl solution}=12.39M$

Hence, the molarity of commercial HCl solution is 12.39 M.

For b:

To calculate the molality of solution, we use the equation:

$Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

$m_{solute}$ = Given mass of solute (HCl) = 38 g

$M_{solute}$ = Molar mass of solute (HCl) = 36.5 g/mol

$W_{solvent}$ = Mass of solvent = 100 - 38 = 62 g

Putting values in above equation, we get:

$\text{Molality of commercial HCl solution}=\frac{38\times 1000}{36.5\times 62}\\\\\text{Molality of commercial HCl solution}=16.79m$

Hence, the molality of commercial HCl solution is 16.79 m.

For c:

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted solution

We are given:

$M_1=6M\\V_1=5.00L\\M_2=12.39M\\V_2=?L$

Putting values in above equation, we get:

$6\times 5=12.39\times V_2\\\\V_2=2.42L$

Hence, the volume of commercial HCl solution needed is 2.42 L.

5 0

3 years ago