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3 years ago

So lost plz help I don’t understand this chemsitry stuff at all and no one will help me

Chemistry

1 answer:

liubo4ka [24]3 years ago

7 0

After careful deliberation, I took the opportunity to find the answers for you.

Answers:
1) _2_Al + _6_HC2H3O2 ->_2_Al(C2H3O2)3 + _3_H2
3) _1_Fe + _2_HBr -> _1_H2 + _1_FeBr2
5) _2_NaOH + _1_ H2SO4 -> _1_Na2SO4 + _2_H2O
7) _2_N2O -> _2_N2 + _1_ O2
9) _1_P4O6 + _2_O2 -> _1_P4O10
11) _2_Mg + _2_CH3COOH -> _2_Mg(CH3COO)2 + _1_H2
13) _2_Al3 + _18_HCl -> _9_H2 + _6_AlCl3
15) _4_KOH + _2_H2SO4 -> _4_H2O + _2_K2SO4
17) _2_NH3 -> _1_N2 + _3_H2
19) _2_SO2 + _1_O2 -> _2_SO3

DONE! *breathes heavily* Alright, after like 30 minutes, these are the answers for your problem.

Hope this helps! :)

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How many particles are in one mole of copper (II) sulfate, CuSO4?

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Name the two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate. Use the charges on th

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Answer:

General equation for a double-displacement reaction:

AB + CD --> AC + BD

• sodium chloride – NaCl copper sulfate – CuSO₄

NaCl + CuSO₄ --> Na₂SO₄ + CuCl₂

The products formed are sodium sulfate and copper (II) chloride.

Copper (II) chloride forms a blue colored solution.

• sodium hydroxide – NaOH copper sulfate – CuSO₄

NaOH + CuSO₄ --> Na₂SO₄ + Cu(OH)₂

The products formed are sodium sulfate and copper (II) hydroxide.

Copper (II) hydroxide forms a blue colored solution.

• sodium phosphate – Na₂HPO₂ copper sulfate – CuSO₄

Na₂HPO₄ + CuSO₄ --> Na₂SO₄ + CuHPO₄

The products formed are sodium sulfate and copper (II) hydrogen phosphate.

Copper (II) hydrogen phosphate forms a blue colored solution.

• sodium chloride – NaCl silver nitrate – AgNO₃

NaCl + AgNO₃--> AgCl + NaNO₃

The products formed are silver chloride and sodium nitrate.

Silver chloride forms a white precipitate.

• sodium hydroxide – NaOH silver nitrate – AgNO₃

NaOH + AgNO₃ --> NaNO₃ + AgOH

The products formed are silver hydroxide and sodium nitrate.

Silver hydroxide forms a white precipitate.

• sodium phosphate – Na₂HPO₄ silver nitrate – AgNO₃

Na₂HPO₄ + AgNO₃ --> NaNO₃ + Ag₂HPO₄

The products formed are sodium nitrate and silver hydrogen phosphate.

Silver hydrogen phosphate forms a colorless solution.

Explanation:

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3 years ago

An atom of an element that has the same number of protons but a different number of neutrons is called a(n): ion nucleus isotope

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It is called an isotope

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Answer:

$\boxed{28.81}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 58.12 44.01

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m/g: 9.511

1. Moles of C₄H₁₀

$\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}$

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

$\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}$

3. Mass of CO₂

$\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}$

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The orbit closest to the nucleus has ___________ energy.

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Answer:

inonic bonds with cavalent bonds

Explanation:

ionic bonds

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