Answer:
Q = 14.578 m³/s
Explanation:
Given
We use the Manning Equation as follows
Q = (1/n)*A*(∛R²)*(√S)
where
- Q = volumetric water flow rate passing through the stretch of channel (m³/s for S.I.)
-
A = cross-sectional area of flow perpendicular to the flow direction, (m² for S.I.)
-
S = bottom slope of channel, m/m (dimensionless) = 2.5% = 0.025
-
n = Manning roughness coefficient (empirical constant), dimensionless = 0.023
-
R = hydraulic radius = A/P (m for S.I.) where
:
-
A = cross-sectional area of flow as defined above,
-
P = wetted perimeter of cross-sectional flow area (m for S.I.)
we get A as follows
A = (B*h)/2
where
B = 5 m (the top width of the flowing channel)
h = (B/2)*(m) = (5 m/2)*(1/2) = 1.25 m (the deep)
A = (5 m*1.25 m/2) = 3.125 m²
then we find P
P = 2*√((B/2)²+h²) ⇒ P = 2*√((2.5 m)²+(1.25 m)²) = 5.59 m
⇒ R = A/P ⇒ R = 3.125 m²/5.59 m = 0.559 m
Substituting values into the Manning equation gives:
Q = (1/0.023)*(3.125 m²)*(∛(0.559 m)²)*(√0.025)
⇒ Q = 14.578 m³/s
Answer:
Q = -68.859 kJ
Explanation:
given details
mass
initial pressure P_1 = 104 kPa
Temperature T_1 = 25 Degree C = 25+ 273 K = 298 K
final pressure P_2 = 1068 kPa
Temperature T_2 = 311 Degree C = 311+ 273 K = 584 K
we know that
molecular mass of
R = 8.314/44 = 0.189 kJ/kg K
c_v = 0.657 kJ/kgK
from ideal gas equation
PV =mRT
WORK DONE
w = 586*(0.1033 -0.514)
W =256.76 kJ
INTERNAL ENERGY IS
HEAT TRANSFER
= 187.902 +(-256.46)
Q = -68.859 kJ
Answer:
The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.
Explanation:
From Fluid Mechanics, we remember that absolute pressure (), measured in pounds per square inch, is the sum of the atmospheric pressure and the working pressure (gauge pressure). That is:
(1)
Where:
- Atmospheric pressure, measured in pounds per square inch.
- Working pressured of the boiler (gauge pressure), measured in pounds per square inch.
If we suppose that and , then the absolute pressure is:
The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.
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