Ask question

Ask question

All categories

Bad White [126]

2 years ago

5

To stop an object that is in motion on a frictionless surface, you stop applying a force.

1 answer:

madreJ [45]2 years ago

8 0

The correct answer is true, you need to be able to stop it, an object in motion remains in motion unless acted upon

You might be interested in

Lauren has a big social studies test coming up. She knows that she needs to spread out her study sessions over a period of time.

tatuchka [14]

The study strategy Lauren is using in spreading her study sessions over a period of time is pacing, which helps the student develop a schedule focused on their own study pace.

<h3>Pacing Study Sessions</h3>

This study strategy of distributing the study into short sessions rather than studying the entire content through one long session is more effective in retaining content and learning.

What happens is that Lauren is using mass repetition processing, which can be compared to a longitudinal wave in physics, with spaces in between, concentrating the initial review close to the proof to ensure retention and avoid forgetting.

Through pacing, Lauren achieves greater motivation to carry out her studies in a concentrated and focused way, helping her to retain and preserve knowledge.

The correct answer is:

Pacing

Find out more information about pacing here:

brainly.com/question/988371

5 0

2 years ago

What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin

Contact [7]

<u>Answer:</u> The total volume of the gaseous products is 1044.29 L

<u>Explanation:</u>

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = $\frac{1}{22.4}\times 116=5.18mol$ of butane

The chemical equation for the combustion of butane follows:

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

<u>For carbon dioxide:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = $\frac{8}{2}\times 5.18=20.72mol$ of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

<u>For water vapor:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = $\frac{10}{2}\times 5.18=25.9mol$ of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

Hence, the total volume of the gaseous products is 1044.29 L

3 0

2 years ago

1 mole of any gas is equivalent to?

iragen [17]

Answer:

22.4 L at standard temperature and pressure.

6 0

3 years ago

One day on her walk home from school, Leann noticed some rust on an old car.

skad [1K]

Answer:

Iron and Oxygen

Explanation:

Fe is Iron and O2 is Oxygen

4 0

2 years ago

The poem "from blossom" inspires readers to appreciate the the joy of the presebt

lana [24]

No... From blossom. Is your answer

7 0

3 years ago